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3 years ago

Don't call me square! While I have four right angles,

Mathematics

1 answer:

Ghella [55]3 years ago

3 0

A rectangle.

If you don’t know how to draw one just look it up.

Hope this helps!

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-6x-4+5x=4<br> What is "x". Please show your work.

4vir4ik [10]

Answer:

first thing to do is combine like terms

now you would have -x-4=4

this is because you added -6x+5x

now you would add 4 to each side

now you would have-x=8

then you would divide the negative because x has to be positive

now you would have x= -8

that is your answer. if you any questions just ask :D

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Help me please.....:)

kozerog [31]

Answer:I don’t know if I’m right but imma have to say G

Step-by-step explanation:

I’m not good at math

8 0

3 years ago

Draw a rectangular fraction model to explain your thinking. Then, write a multiplication sentence. What is 4/9 x 3/8 ?

ELEN [110]

Answer:

The multiplication sentence is 4/9*3/8=1/6

then for the rectangular fraction model draw two rectangles and in the first one draw 9 boxes and shade in 4. Then, in the second one draw 8 boxes and shade 3.

Step-by-step explanation:

This is an example:

8 0

3 years ago

plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

4 0

4 years ago

Multiply the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending pow

marshall27 [118]

The easiest method of multiplying polynomials, in my experience, is the FOIL method. Honestly, I couldn't tell you what the letters stand for anymore, but I definitely remember how to do it. It's just distribution.
(6x+1)(5x+8)
Multiply the 6x by 5x and 8, then the 1 by 5x and 8:
30x²+48x+5x+8
Then combine like terms:
30x²+53x+8

5 0

3 years ago