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Minchanka [31]
3 years ago
14

What is an equation of the line that passing through the points (-2, -5) and (4, 7) ?

Mathematics
1 answer:
monitta3 years ago
6 0

Answer:

y=2x-1

Step-by-step explanation:

Use the slope-intercept formula: y=mx+b where m is slope and b the y-intercept.

(-2,-5)(4,7)

Use the slope formula for when you have two points:

\frac{y(2)-y(1)}{x(2)-x(1)}=\frac{rise}{run}

Rise over run is the change in the y-axis over the change in the x-axis. Insert values:

\frac{7-(-5)}{4-(-2)}

Simplify parentheses (negative+negative=positive)

\frac{7+5}{4+2}

Simplify

\frac{12}{6}=2

2 is the slope:

y=2x+b

Now use one of the points to find the y-intercept by substituting the x and y values into the equation. Solve for b:

(4,7)

y=2x+b\\7=2(4)+b

7=8+b\\7-8=8-8+b\\7-8=b\\-1=b\\b=-1

The y-intercept is -1. Insert into the equation. Change the + symbol to -:

y=2x-1

Done.

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What is the value of x in the equation 3x-5=1/2x+2x
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Answer:

10

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x−5=

1

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1

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Step 2: Subtract 5/2x from both sides.

3x−5−

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x−

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1

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Step 4: Multiply both sides by 2.

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4 0
3 years ago
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Step-by-step explanation:

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2 years ago
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