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2 years ago

Which statements are true about dilations? Select all that apply.

2 answers:

4 0

A, C, and E. This is because dilations change the size/length of the sides = the sides cannot be congruent, however the angles are the same.

Lostsunrise [7]2 years ago

4 0

Answer with explanation:

Dilation of any geometrical shape means, producing an image , that has larger or smaller size than Pre image,

→Image > Pre-Image,≡If dilation factor > 1

→Image < PreImage,≡If 0<Dilation factor<1.

But , Image and Preimage are Similar in both the cases.

So,out of the five statement, the correct statements are:

1. Dilations produce images that are similar to the pre-image.

3. Dilations produce images that have angles that are congruent to the pre-image.

5. Dilations produce images that have sides that are proportional to the pre-image.

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Isaac and his wife received an award of $ 9,000 each for their work as researchers.

V125BC [204]

Answer:

Step-by-step explanation:

I don't know if I did it wrong because I got 4,206.27 but I probably did

3 0

2 years ago

I WILL GIVE FIRST ANSWER BRAINLIEST

Ostrovityanka [42]

Answer:

1) Papa Ron's(60$ per shift)

2) Little Squeezer's(3$ per pizza)

3) Little Squeezer's

Explanation:

1) A shift's pay is money given for simply entering the workplace(at least in this problem!) So it would be money given whether Tony has delivered pizzas or not. It would be numerically equal to his pay when he doesn't deliver any pizzas.

Bombino's offers 56$ per shift(stated in Q),

Little Squeezer's offers 48$ when he has delivered no pizzas, thus it must be his pay per shift.

Pizza Tent offers 52$ when he has delivered zero pizzas(substitute

in the given function S)

The graph shows that Papa Ron's offers 60$ when no pizzas are delivered. This is clearly the best pay per shift. (when

)

2) Bombino's: 2.5$ per pizza(stated)

Little Squeezers gives 6$ more than his default pay(which he would get even if he didn't deliver anything) when Tony has delivered 2 pizzas. Thus it gives 3$ per pizza.

Pizza Tent gives 2.75$ per pizza. This can be inferred from S.

2.75

Here, 52 is his default pay. He gets 2.75$ for each pizza delivered, as it is the coefficient of

Papa Ron's pay per pizza can be calculated by finding the slope of the line in the graph.

Here, I take the points (64, 2) and (60, 0).

−

Thus the pay is 2$ per pizza delivered. For simplicity, I will define Papa Ron's pay as a function

(Notice that 2 is the slope and 60 is the base pay)

Clearly, Little Squeezer's offers the most per pizza.

3) To figure this question out, we will need to find pay when Tony delivers 20 pizzas for each restaurant.

Bombino's pays

2.5

(

)

106

Little Squeezer's pays

(

)

108

Pizza Tent pays

2.75

(

)

107

Papa Ron's pays

(

)

100

So, Little Squeezer's is the company that pays best when Tony is delivering over 19 pizzas.

(This is a long question, I may have made a mistake. Please correct me if that is the case.)

Step-by-step explanation:

8 0

2 years ago

How many lines of symmetry does a kite have? 4 3 1 2

skelet666 [1.2K]

A typical quadrilateral kite (kinda looks like a diamond) only has 1 line of symmetry

4 0

2 years ago

According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe

Ann [662]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1 - p)}{n}}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .