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3 years ago

I have 1 question someone who is good at math plz. help I'm giving 12 pts.

Mathematics

2 answers:

koban [17]3 years ago

6 0

Answer:so the answer is 224 dollars

Step-by-step explanation:

30 percent of 320 is about 96 dollars saving

I am Lyosha [343]3 years ago

3 0

$224 for the camping gear

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A car goes from rest to 50 m/s in 5 seconds. What is the acceleration?

AVprozaik [17]

The acceleration is 10 because 50 divided by 5 is 10.

3 0

3 years ago

A town has a population of 5000 and grows at 4% every year. To the nearest year, how long will it be until the population will r

Rus_ich [418]

Answer:

About 21.457 years

Step-by-step explanation:

You can solve this by setting up a simple equation.

$5000\cdot 1.04^x \geq 11600$

$1.04^x \geq 2.32$

log base 1.04 2.32=x

$x\approx 21.457$ years

Hope this helps!

8 0

3 years ago

7t=x,for t .what is the formula

Andrei [34K]

The formula for t would be x/7.

In order to find this, we simply follow the order of operations to solve for t.

7t = x ----> Divide both sides by 7

t = x/7

6 0

3 years ago

2x + 6 = 2x - 2<br> ??????????

svp [43]

2x-6=2x+2

We move all terms to the left:

2x-6-(2x+2)=0

We get rid of parentheses

2x-2x-2-6=0

We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation

6 0

3 years ago

A family wants to save for college tuition for their daughter. What continuous yearly interest rate r% is needed in their saving

sergey [27]

Answer:

The continuous yearly interest is 22.5% per year.

Step-by-step explanation:

Continuous yearly interest:

Continuous yearly interest is defined as the sum of the interest comes from principle and the interest comes from interest.

The formula for continuous interest yearly is

$A=Pe^{rt}$

where A = The final amount =$110,000

P= principle =$4,700

r= rate of interest

t= time (in year)= 14 years

$\therefore 110,000= 4,700e^{r\times 14}$

$\Rightarrow e^{14r}= \frac{110,000}{4,700}$

Taking ln both sides

$\Rightarrow ln e^{14r}= ln(\frac{110,000}{4,700})$

$\Rightarrow {14r}= ln(\frac{1100}{47})$

$\Rightarrow r=\frac{ln( \frac{1100}{47})}{14}$

$\Rightarrow r = 0.225$ (approx)

The continuous yearly interest is 0.225 = 22.5% per year.

4 0

3 years ago