All categories

4 years ago

1.19082852E14 to number

Mathematics

1 answer:

cricket20 [7]4 years ago

5 0

Answer:

119,082,850,000,000

Step-by-step explanation:

1.1908285E14

E14 means the decimal point should be moved 14 places to the right:

119082850000000.00

You might be interested in

A spray irrigation system waters a section of a farmer’s field. If the water shoots a distance of 85 feet, what is the area that

gtnhenbr [62]

Answer:

3,781

Step-by-step explanation:

To solve this problem, we will find the area of the whole circle and use that to find teh area of the 60º section.

First, recognize the formula for the area of a circle:

A = 3.14 $r^{2}$

In this scenario, the radius (<em>r</em>) is 85 feet:

A = 3.14(85 $)^{2}$

A circle is 360º and we only require the area of 60º. 360º / 60º = 6 so we will divide by 6:

A = $\frac{3.14(85)^{2} }{6}$

Finally, we will simplify and round:

A = 3,781

7 0

3 years ago

Write a fraction that is less than 1/3 using 1 as a numerator. Then explain why the answer you chose is less than 1/3.

sammy [17]

1/4, because in 1/3, you would only need 3 parts to get one whole, but in 1/4, you would need 4 parts to get a whole.

3 0

4 years ago

Suppose a certain manufacturing company produces connecting rods for 4- and 6-cylinder automobile engines using the same product

gregori [183]

Answer:

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

Step-by-step explanation:

The cost for the four cylinder production line is $C_4 = \$2,100$

The cost for the six cylinder production line is $C_6 = \$3,500$

The manufacturing cost for each four cylinder is $M_4= \$13$

The manufacturing cost for each six cylinder is $M_6= \$16$

The weekly production capacity for 4 cylinder connecting rod is $W_4 = 5,000$

The weekly production capacity for 6 cylinder connecting rod is $W_6 = 8,000$

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

3 0

4 years ago

3. a. Simplify (2x + y) (x-7)<br>b. Find the truth set of 2x-3 +3 = -1<br>

aksik [14]

Answer: b. X=-1/2

Step-by-step explanation:

2x-3+3=-1-3 and +3 cancel each other

2x=-1 both sides divided by 2

X=-1/2

8 0

4 years ago

Here's a recipe for pancakes:

sweet [91]

Answer:

Milk: 1000 ml

Flour: 480 g

Butter: 250 g

Step-by-step explanation:

To calculate the amount of butter you have to figure out more flour she used.

First, 480 ÷ 120 = 4 So she uses 4 times the amount of flour.

Then, 60 × 4 = 240

Next, you need the amount of milk so we also multiply by 4.

250 × 4 = 1000

Lastly, have a great day!

6 0

3 years ago