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sweet [91]
2 years ago
10

%5B3%5D%7B125%7D%20%20%2B%20%20%7B9%7D%5E%7B3%7D%20%20%3D%20....%7D%20" id="TexFormula1" title=" \bf{ {15}^{2} \times {3}^{2} \div \sqrt[3]{125} + {9}^{3} = ....} " alt=" \bf{ {15}^{2} \times {3}^{2} \div \sqrt[3]{125} + {9}^{3} = ....} " align="absmiddle" class="latex-formula">​
Mathematics
1 answer:
34kurt2 years ago
7 0

\\ \tt\Rrightarrow 15^2\times 3^2\div \sqrt[3]{125}+9^3

\\ \tt\Rrightarrow 3^25^2\times 3^2\div 5^1+3^33^3

\\ \tt\Rrightarrow 3^45^1\div 3^6

\\ \tt\Rrightarrow 3^{-2}5

\\ \tt\Rrightarrow \dfrac{1}{3^2}5

\\ \tt\Rrightarrow \dfrac{5}{9}

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Step-by-step explanation:

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The sum of an integer and 6 is twice as big as the number itself. What is the integer?Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!I will bra
laila [671]

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7 0
4 years ago
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iren [92.7K]

Answer:

1a)  Length = 7x + 3  & Width = 4x - 2

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Step-by-step explanation:

1a)

The length given as words is "3 more than 7 times x"

The width given as words is "4 times x minus 2"

The expression for length would be  7x + 3

The expression for width would be 4x - 2

1b)

The area is length * width

Since we already know the algebraic expressions for length and width from part (a) above, we use the formula:

Area = (7x+3)(4x-2) = 28x^2 -14x + 12x - 6 = 28x^2 -2x -6

Area = 28x^2 -2x -6

1c)

Given x = 10, we put this into the area expression we found in (b) above.Let's see:

28x^2 -2x -6\\=28(10)^2 -2(10) -6\\=2774

Area = 2774 sq. m

2.

We can group the first two terms and next two terms and write up:

xy-4y+7x-28\\(xy-4y)+(7x-28)\\y(x-4)+7(x-4)\\(x-4)(y+7)

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3 years ago
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Answer:

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Step-by-step explanation:

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