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sweet [91]
2 years ago
10

%5B3%5D%7B125%7D%20%20%2B%20%20%7B9%7D%5E%7B3%7D%20%20%3D%20....%7D%20" id="TexFormula1" title=" \bf{ {15}^{2} \times {3}^{2} \div \sqrt[3]{125} + {9}^{3} = ....} " alt=" \bf{ {15}^{2} \times {3}^{2} \div \sqrt[3]{125} + {9}^{3} = ....} " align="absmiddle" class="latex-formula">​
Mathematics
1 answer:
34kurt2 years ago
7 0

\\ \tt\Rrightarrow 15^2\times 3^2\div \sqrt[3]{125}+9^3

\\ \tt\Rrightarrow 3^25^2\times 3^2\div 5^1+3^33^3

\\ \tt\Rrightarrow 3^45^1\div 3^6

\\ \tt\Rrightarrow 3^{-2}5

\\ \tt\Rrightarrow \dfrac{1}{3^2}5

\\ \tt\Rrightarrow \dfrac{5}{9}

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If the tree grows an additional 10 feet, what is the new angle of
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Answer:

  B)  47.1°

Step-by-step explanation:

The tangent relation is useful here.

  Tan = Opposite/Adjacent

The original height of the tree is the side of the triangle that is opposite the angle of elevation:

  Opposite = Adjacent × Tan

  original height = (25 ft)×tan(34°) ≈ 16.863 ft

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After growing an additional 10 ft, the tree has a height of ...

  16.863 ft + 10 ft = 26.863 ft

Then the angle of elevation is found from ...

  tan(angle) = (26.863 ft)/(25 ft) ≈ 1.07451

  angle of elevation = arctan(1.07451) ≈ 47.057°

The angle of elevation to the top of the tree is about 47.1°.

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2 years ago
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8 0
3 years ago
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Dvinal [7]
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