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Umnica [9.8K]
3 years ago
10

Please any tricks for solving bearings in maths​

Mathematics
1 answer:
Triss [41]3 years ago
5 0

Answer:

A bearing is an angle, measured clockwise from the north direction. Below, the bearing of B from A is 025 degrees (note 3 figures are always given). The bearing of A from B is 205 degrees.

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Matrix fractions 1/2+2/6. I don't understand the steps in this.​
Effectus [21]

Answer: 5/6

Step-by-step explanation:

You have to multiply the denominator and numerator by 3 to get the same denominato. Then you ONLY add the numerator. 3/6 + 2/6 = 5/6.

5 0
2 years ago
The surface area for a rectangular prism with a square base is SA=2s2+4sh.
umka21 [38]
2*2*2=8+4*2*4=40 ....
6 0
3 years ago
Read 2 more answers
The sum of two numbers is 62 the smaller number is 6 less than the larer number what are the numbers
muminat
X= larger number
x-6= smaller number

x + (x - 6)= 62
combine like terms

2x - 6= 62
add 6 to both sides

2x= 68
divide both sides by 2

x= 34 larger number


SMALLER NUMBER
x - 6= 34 - 6= 28


ANSWER: The smaller number is 28 and the larger number is 34.

Hope this helps! :)
5 0
3 years ago
How many 3/4s are in 6
Pepsi [2]
Hey there!
Let's first find an easier situation.
If we're saying:
How many fives are in ten?
We're doing 10 divided by 5, because we're seeing how many 5's go into 10.
It's no different here.
We will be doing 6 divided by 3/4, just as we did with our simpler situation.
Using our "keep, switch, flip" rule (keep first term, change to multiplication, take reciprocal of second term)
we get:
6 divided by 3/4
=
6 * 4/3
= 24/3
= 8 3/4's in 6.

Hope this helps!
7 0
3 years ago
Members of the millennial generation are continuing to be dependent on their parents (either living with or otherwise receiving
Morgarella [4.7K]

Answer:

a)

\bf H_0: The mean of adults aged 18 to 32 that continue to be  dependent on their parents is 0.3

\bf H_a: The mean of adults aged 18 to 32 that continue to be  dependent on their parents is greater than 0.3

b) 34%

c) practically 0

d) Reject the null hypothesis.

Step-by-step explanation:

a)

Since an individual aged 18 to 32 either continues to be dependent on their parents or not, this situation follows a Binomial Distribution and, according to the previous research, the probability p of “success” (depend on their parents) is 0.3 (30%) and the probability of failure q = 0.7

According to the sample, p seems to be 0.34 and q=0.66

To see if we can approximate this distribution with a Normal one, we must check that is not too skewed; this can be done by checking that np ≥ 5 and nq ≥ 5, where n is the sample size (400), which is evident.

<em>We can then, approximate our Binomial with a Normal </em>with mean

\bf np = 400*0.34 = 136

and standard deviation

\bf \sqrt{npq}=\sqrt{400*0.34*0.66}=9.4742

Since in the current research 136 out of 400 individuals (34%) showed to be continuing dependent on their parents:

\bf H_0: The mean of adults aged 18 to 32 that continue to be  dependent on their parents is 0.3

\bf H_a: The mean of adults aged 18 to 32 that continue to be  dependent on their parents is greater than 0.3

So, this is a r<em>ight-tailed hypothesis testing. </em>

b)

According to the sample the proportion of "millennials" that are continuing to be dependent on their parents is 0.34 or 34%

c)

Our level of significance is 0.05, so we are looking for a value \bf Z^* such that the area under the Normal curve to the right of \bf Z^* is ≤ 0.05

This value can be found by using a table or the computer and is \bf Z^*= 1.645

<em>Applying the continuity correction factor (this should be done because we are approximating a discrete distribution (Binomial) with a continuous one (Normal)), we simply add 0.5 to this value and </em>

\bf Z^* corrected is 2.145

Now we compute the z-score corresponding to the sample

\bf z=\frac{\bar x -\mu}{s/\sqrt{n}}

where  

\bf \bar x= mean of the sample

\bf \mu= mean of the null hypothesis

s = standard deviation of the sample

n = size of the sample

The sample z-score is then  

\bf z=\frac{136 - 120}{9.4742/20}=16/0.47341=33.7759

The p-value provided by the sample data would be the area under the Normal curve to the left of 33.7759 which can be considered zero.

d)

Since the z-score provided by the sample falls far to the left of  \bf Z^* we should reject the null hypothesis and propose a new mean of 34%.

7 0
2 years ago
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