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2 years ago

Workout the problem and explain it in paragraph form

Mathematics

2 answers:

Arada [10]2 years ago

7 0

I think it should be 12

Anna71 [15]2 years ago

3 0

He answer of this question is 17

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An artist wants to create a painting on a semicircle canvas with a radius of 13 feet. He wants to surround the canvas with a pie

kodGreya [7K]

Answer: I forgot i remember the answer in my head I forgot..

Step-by-step explanation:

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2 years ago

Help me with 26 ASAP Please show work Random Answers will be moderated! Thanks :)

vfiekz [6]

First, convert the distance of a typical marathon to kilometers.
1 mi = 1.609 km
26.2 miles = 42.165 km

Divide this distance by Allan's average speed to get his average time.

42.165 km / 12 km/hr = 3.514 hours

4 0

3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

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2 years ago

What is the initial value of the equation shown?

hodyreva [135]

C. −6, is the best option

7 0

3 years ago

Read 2 more answers

What’s the correct answer?

Marat540 [252]

Answer:

D is the correct answer

Step-by-step explanation:

can i have brainliest please im almost ambitious

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3 years ago