127.40/26 = $4.90 per pound
18 * 4.9 = $88.20
It would cost $88.20
Answer:
Altitude of the plane is 0.5 miles.
Step-by-step explanation:
From the figure attached,
An airplane A is at height h miles observes a small airstrip at D and a factory at F, 4.8 miles apart from D.
Angle of depressions for the airstrip is 13.1° and the factory is 4.1°.
We have to calculate the airplane's altitude h.
From ΔABF,
tan4.1 = 
h = 0.07168(x + 4.8) -----(1)
From ΔABD,
tan13.1 = 
h = 0.2327x -----(2)
From equation (1) and (2),
0.07168(x + 4.8) = 0.2327x
0.2327x - 0.07168x = 4.8×0.07168
0.161x = 0.344
x =
miles
From equation (2),
h = 0.2327×2.137
h = 0.4972 miles
h ≈ 0.5 miles
Therefore, 0.5 miles is the altitude of the plane.
Answer:
if a:c=2:3 andb:c=3:4therefore a:c=2:4
Answer:
x> 2
Step-by-step explanation:
Multiply by 6
2x6=12
5x+2>12
Move the 2 and make it subtraction
5x>12-2
Subtract 12-2=10
5x>10 divide by 5
X>2
Answer:
c
Step-by-step explanation: