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Inga [223]
4 years ago
12

An equation is shown below:

Mathematics
2 answers:
Airida [17]4 years ago
8 0
So you would do 5*2x +5*-8 +15=-15
Then simplify so it would be 10x + -40 + 15 = -15
Then add -40 and 15 together
Then it would be 10x + -25 = -15
Then add 25 to -25 and -15
So it would be 10x = 10
And then divide 10 from 10 with would be 1 so x = 1
Kaylis [27]4 years ago
5 0
5(2x-8)+15=-15 (subtract 15 from each side)
5(2x-8)=-30 (divide both sides by 5)
2x-8=-6 (add 8 to each side)
2x=2 (divide both sides by 2)
x=1 


Check your work
5(2x-8)+15=-15
5(2(1)-8)+15=-15
5(2-8)+15=-15
5(-6)+15=-15
-30+15=-15
-15=-15
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2x+3=10<br> Simplify to the nearest term.
Genrish500 [490]

Answer:

x = 4.

Step-by-step explanation:

2x + 3 = 10.

Simplify 3 - 10 = -7.

2x = -7.

Divide 2x = -7 to 4.

Hope this helps!

Have a good day ma'am/sir.

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3 years ago
Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.
lukranit [14]

The x-coordinates of \triangle S'T'U' will be the negation of the x-coordinates of \triangle STU

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for \triangle STU and \triangle S'T'U'

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of \triangle STU are

S = (4,5)      

T = (5,9)

U=(3,8)

Refer to attachment for illustrations

<u>(1) Reflect </u>\triangle STU<u> over y-axis and describe the transformation</u>

To reflect \triangle STU across the y-axis, the following rule must be followed

(x,y) \to (-x,y)

This means that:

S = (4,5) \to S' = (-4,5)

T = (5,9) \to T' = (-5,9)

U=(3,8) \to U'=(-3,8)

<u>The description of the </u><u>transformation </u><u>is as follows:</u>

Notice that the signs of the x-coordinates \triangle STU and \triangle S'T'U' of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

<u>(2) Compare the segments and the line of reflection</u>

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

S = |4| = 4

The distance between S' and the y-axis is:

S' = |-4| = 4

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

<u>From T and T' to the y-axis is:</u>

T =|5| =5

T' =|-5| =5

Read more at:

brainly.com/question/938117

8 0
3 years ago
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lora16 [44]
I would say B. By multiplying the first equation by -5, you create -5y. If you add that to the second equation, your cancelling out the 5y term, and get a new equation with only z and a constant.
8 0
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Solve the following:<br><br> one and two fourths plus three and three fourths
tino4ka555 [31]

Answer:

5 and 1/4 is the answer to your problem

Step-by-step explanation:

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