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3 years ago

14

CAN SOMEONE PLEASE HELP MEE???

1 answer:

pickupchik [31]3 years ago

7 0

Answer:

C. $y = \frac{1}{3}x$

Step-by-step explanation:

All linear equations reflect that the line graph is the straight line.

The linear equation reflecting a straight line has the formula as following: $y = a*x+b$

According to the table, the line graph cross four points: A (-3; -1); B(0;0); C(3;1); D(6;2), which means that the x, y of each point would fit the equation.

So that, we replace the x, y of each point in the equation and have:

1) -1 = a*-3 +b

2) 0 = b

3) 1 = a*3 + b

4) 2 = a*6 + b

From these 4 equations, it can be calculated that: a = 1/3; b = 0

So that the linear equation corresponds to the line graph is: $y = \frac{1}{3}x$

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Find the length of arc AB

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Answer:

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Step-by-step explanation:

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3 years ago

Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

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To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

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$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

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Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

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$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

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Therefore, the variance of combined set is 15.4.

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3 years ago

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DENIUS [597]

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viktelen [127]

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3 years ago

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