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Sholpan [36]
3 years ago
12

Write as a product: ac^4-c^4+ac^3-c^3

Mathematics
1 answer:
Anna11 [10]3 years ago
8 0

I ran out of time and it erased my work. Sorry.

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Find the lcm of 3x-1/4=2
Scilla [17]

Answer:

x=3

Step-by-step explanation:

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NO LINKS!!! PLS HELP ME IM TRYING TO GRADUATE PLSSS !!! Find the midpoint of the segment below and enter its coordinates as an
Leto [7]

Answer:

x = 5/2 , y = -7/2

Step-by-step explanation:

<em>r's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>finding</em><em> </em><em>midpoint</em><em> </em><em>=</em><em>.</em><em>(</em><em> </em><em>X1</em><em> </em><em>+</em><em> </em><em>X</em><em>2/</em><em>)</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>(</em><em>Y1+</em><em>Y2)</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>putting</em><em> </em><em>the </em><em>value</em><em> </em><em>of </em><em>in </em><em>formula</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>x=</em><em> </em><em> </em><em>4</em><em>+</em><em>1</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>1</em><em>-</em><em>6</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>x </em><em>=</em><em> </em><em>5</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>7</em><em>/</em><em>2</em>

<em>hope</em><em> it</em><em> helps</em>

3 0
3 years ago
The diameter of a u.s quarter is 24.26 millimeters. How long is a line of 37 quarters laid edge to edge?
wariber [46]
All u do is multiply 24.26 and 37 which gives u <span>897.62...
897.62 mm long is your answer.</span>
4 0
3 years ago
Read 2 more answers
H(x)=x^2-1 what is the average rate of change of h over the interval −3≤x≤−1
Allisa [31]

slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(x)=x^2-1 \qquad \stackrel{-3\leqslant ~~x~~\leqslant -1}{\begin{cases} x_1=-1\\ x_2=-3 \end{cases}}\implies \cfrac{h(-3)-h(-1)}{-3-(-1)} \\\\\\ \cfrac{[(-3)^2-1]~~ -~~[(-1)^2-1]}{-3+1}\implies \cfrac{8~~-~~0}{-2}\implies -4

7 0
2 years ago
Which of the following transformations always preserves the dimensions of a figure
Rina8888 [55]

Answer:

In Reflection, rotation and translation, dimensions of the figure are always preserved

Step-by-step explanation:

8 0
3 years ago
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