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snow_tiger [21]
3 years ago
10

Find a coordinate pair for a point on the graph of 2x + 6y = 2

Mathematics
1 answer:
allochka39001 [22]3 years ago
3 0

Answer:

(0,1/3)

(1,0)

(2,-1/3)

Step-by-step explanation:

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Use both a fraction and a decimal number to represent the shaded amount. Write the fraction in simplest form.
klemol [59]

Answer:

see below

Step-by-step explanation:

2/10 = 1/5 = 0.2 = 20%

5 0
3 years ago
Read 2 more answers
Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1 1/2 times its abscissa.
rosijanka [135]

Answer:

(2, 3)

Step-by-step explanation:

2x + 5y = 19

5y = -2x + 19

y = -\frac{2}{5} x + \frac{19}{5}

P(abscissa, ordinate)

P(x, 1.5x)

P(2, 3)

3 = -\frac{2}{5} (2) + \frac{19}{5}

3 = -\frac{4}{5} + \frac{19}{5}

3 = 15/5

3 = 3

8 0
3 years ago
Lixins monthly income consists of a basic salary of $500 and a commission of 4percent on her sales for the month.If her income i
Harman [31]

Answer:

Lixins monthly sales = $18,000

Step-by-step explanation:

Let x be the total sales.

Given:

Basic salary = $500

Commission on sales = 4% = 0.04

Monthly income = $1220

We need to find her sales for the month.

Solution:

First we write the equation for given situation:

Total\ sales = Basic\ Salary + 0.04(Total\ sales)

S = 500 + 0.04x

1200=500+0.04x

0.04x=1220-500

0.04x=720

x = \frac{720}{0.04}

x = \$18,000

Therefore, Lixins monthly sales are $18,000.

8 0
3 years ago
Factor the expression. k^2 – 100h^2
wolverine [178]
K^2 - 100h^2
(k - 10h)(k + 10h)
5 0
3 years ago
A researcher believes that there is a difference in how cautious male stray cats and female stray cats are when approaching peop
Anika [276]

Answer:

The null hypothesis is that there is no difference in the mean number of male and female cats

H₀; μ₂ - μ₁ = 0

Step-by-step explanation:

The given parameters are;

The given percentage of male stray cat population = 50%

The given percentage of female stray cat population = 50%

The number of areas the researcher visits, n = 15

The number of stray male cats he finds = 11

The kind of test to be performed = Sign test

The significance level, α = 0.05

A) Therefore the null hypothesis is H₀; μ₂ - μ₁ = 0

The alternative hypothesis is Hₐ; μ₂ - μ₁ ≠ 0.

5 0
3 years ago
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