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PtichkaEL [24]
2 years ago
11

Can someone please help me with 44. And 45?

Mathematics
2 answers:
Angelina_Jolie [31]2 years ago
6 0

Problem 44

The term "bisect" means "cut in half".

Since BD bisects angle ABC, this means the smaller angles ABD and DBC are congruent.

angle ABD = angle DBC

x+15 = 4x-45

15+45 = 4x-x

60 = 3x

3x = 60

x = 60/3

x = 20

<h3>Answer:  x = 20</h3>

========================================================

Problem 45

We use the same idea as the previous problem

angle ABD = angle DBC

2x+35 = 5x-22

35+22 = 5x-2x

57 = 3x

3x = 57

x = 57/3

x = 19

<h3>Answer: x = 19</h3>
OLga [1]2 years ago
6 0

Answer:

44. x = 20

45. x = 19

Step-by-step explanation:

44:

x + 15 = 4x - 45

Subtract x from both sides.

15 = 3x - 45

Add 45 to both sides.

60 = 3x

Divide both sides by 3.

x = 20

45:

2x + 35 = 5x - 22

Subtract 2x from both sides.

35 = 3x - 22

Add 22 to both sides.

57 = 3x

Divide both sides by 3.

x = 19

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Hope that helped!

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1 year ago
ANSWER THIS TO GET 20 POINTS<br><br> what does a ratio of 2:1 mean
sdas [7]

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It means 2/1

Step-by-step explanation:

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2 years ago
What is the range for f(x) = 2^x
Natali [406]

Given the function:

f(x)=2^x

The function can also be written as:

y=2^x

The range of the function will be all set of y values.

To find the range, let's graph the function below.

We have:

From the graph above, all possibe y values range from 0 to infinity.

Therefore, the range of the function is from zero infinity.

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6 0
1 year ago
Need help not sure about my answers
shusha [124]

Answer:

  x = 0, x = 1

Step-by-step explanation:

Both graphs correctly plot f(x).

Only the bottom graph correctly plots g(x).

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2 years ago
Find a positive number for which the sum of it and its reciprocal is the smallest​ (least) possible. Let x be the number and let
Allisa [31]

Answer:

S(x) = x + \frac{1}{x} --- Objective function

Interval = \{x:x=1\}

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

x + \frac{1}{x}

Hence, the objective function is:

S(x) = x + \frac{1}{x}

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

S'(x) = 1 - \frac{1}{x^2}

Equate S'(x) to 0 in order to solve for x

0 = 1 - \frac{1}{x^2}

Subtract 1 from both sides

0 -1 = 1 -1 - \frac{1}{x^2}

-1 = - \frac{1}{x^2}

Multiply both sides by -1

1 = \frac{1}{x^2}

Cross Multiply

x^2 * 1 = 1

x^2  = 1

Take positive square root of both sides because x is positive

\sqrt{x^2} = \sqrt{1

x = 1

Representing x using interval notation, we have

Interval = \{x:x=1\}

To get the smallest sum, we substitute 1 for x in S(x) = x + \frac{1}{x}

S(1) = 1 + \frac{1}{1}

S(1) = 1 + 1

S(1) = 2

<em>Hence, the smallest sum is 2</em>

3 0
3 years ago
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