Answer:
km
Step-by-step explanation:
The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of 
km and 
km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, 
, where 
and 
are the lengths of the triangle's legs and 
is the length of the triangle's hypotenuse. In this case, we know what and are, and we need to solve for c, so after substituting the given values of and into to solve for c, we get:
(Substitute 
and 
into the equation)
(Evaluate the squares on the LHS)
(Simplify the LHS)
(Symmetric Property of Equality)
(Take the square root of both sides of the equation)
(Simplify)
is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately km away from its base. Hope this helps!
Answer:-5.8
Explanation:4.5-8.3=-3.8 -3.8-2=5.8
Answer:8
Step-by-step explanation: plug in 0 for y then solve
Answer:
Step-by-step explanation:
From the question we are told that:
Percentage of Green beads 
Percentage of Red beads 
Percentage of Purple beads 
Therefore
Probability of choosing a Green bead is
Probability of choosing a Red bead is
Generally the equation for choosing a green bead then a red bead is mathematically given by
Since Outcomes are independent
Answer:
x = 50*e∧ -t/100
Step-by-step explanation:
We assume:
1.-That the volume of mixing is always constant 300 gallons
2.-The mixing is instantaneous
Δ(x)t = Amount in - Amount out
Amount = rate * concentration*Δt
Amount in = 3 gallons/ min * 0 = 0
Amount out = 3 gallons/min * x/ 300*Δt
Then
Δ(x)t/Δt = - 3*x/300 Δt⇒0 lim Δ(x)t/Δt = dx/dt
dx/dt = - x/100
dx/ x = - dt/100
A linear first degree differential equation
∫ dx/x = ∫ - dt/100
Ln x = - t/100 + C
initial conditions to determine C
t= 0 x = 50 pounds
Ln (50) = 0/100 * C
C = ln (50)
Then final solution is:
Ln x = - t/100 + Ln(50) or
e∧ Lnx = e ∧ ( -t/100 + Ln(50))
x = e∧ ( -t/100) * e∧Ln(50)
x = e∧ ( -t/100) * 50
x = 50*e∧ -t/100
