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3 years ago

sam said that any integer is the same distance from zero as the opposite of its opposite. Is sam correct?

Mathematics

2 answers:

ziro4ka [17]3 years ago

8 0

Yes Sam is correct hope that helped would you like an explanation

Lorico [155]3 years ago

5 0

Yes indeed Sam is correct

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Randy rented a rectangular storage shed with the volume of 357 ft does it sheds height is 8 and 1/2 ft and the width of is 6 ft

ollegr [7]

Answer:

7 feets

Step-by-step explanation:

Volume of shed, V = 357 feet³

Height of shed, H= 8 1/2 fts

Width of shed, W = 6 ft

Using the relation :

Volume = Length * width * height

357 = L * 6 ft * 17/2 feets

357 feets³ = L * 51 feets²

L = 357 feets³ / 51 feets²

Length, L = 7 feets

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3 years ago

How many times does 9 go into 12?

tamaranim1 [39]

Answer:

one time.

Step-by-step explanation:

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3 years ago

The eye of a dinosaur has 9 yellow, 2 white, 4 black,

vivado [14]

20:5
The total number of jelly beans is 20, and there are 5 orange jelly beans. This is a total to part ratio because it’s comparing the entirety to a part.

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4 years ago

Determine if the equation is linear 2x y=4,

Juliette [100K]

Determine whether each equation is a linear equation. ... –2x – 3 = y .... linear. 16. 4y. 2. + 9 = –4. SOLUTION: Since y is squared, the equationcannot be written in standard form.

4 0

4 years ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X \geq 5)$

And we can use the complement rule:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

4 0

3 years ago