Using proportions, it is found that the correct time when it reads 10:30pm is of 9:40 pm.
<h3>What is a proportion?</h3>
A proportion is a fraction of total amount, and the measures are related using a rule of three.
In this problem, when 56 minutes have passed, the clock indicates that 60 minutes have passed. Hence, what is the time passed when the clock indicates that 12 hours and 30 minutes, that is, 60 x 12 + 30 = 750 minutes have passed?
Hence, the <em>rule of three</em> is:
56 minutes - 60 minutes
x minutes - 750 minutes
Applying cross multiplication:
700 minutes is 660/60 = 11 hours + 40 minutes after 10:00 am, hence the correct time is of 9:40 pm.
You can learn more about proportions at brainly.com/question/24372153
Answer:
B : 5/6
Step-by-step explanation:
By doing some simple fraction, this would be the only thing that'd be correct!
Sorry but I’m lost what are you talking about
3 rows of 12
9 rows of 4
2 rows of 18
6 rows of 6
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.
B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.
Flight time = 2* ascendent time
ascendent time => final vertical velocity, Vy, = 0
sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s
Vy = Voy - gt = 0 => Voy = gt = t = Voy / g
Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)
t = 18.03 m/s / 10 m/s^2 = 1.83 s
This is the ascendant time going upward.
The flight time is 2*1.83 = 3.66 s
Horizontal motion
Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s
Vx = x / t => x = Vx*t
Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m
c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
