Answer:
5. LCM of 7 and 14: <u> </u><u> </u><em><u>1</u></em><em><u>4</u></em><em><u>. </u></em>
multiples of 7: <u> </u><u> </u><u>7</u><u>,</u><u> </u><u>1</u><u>4</u><u> </u>
multiples of 14: <u> </u><u>1</u><u>4</u><u> </u>
LCM of 8 and 12: <u> </u><u> </u><em><u>2</u></em><em><u>4</u></em><em><u>. </u></em>
multiples of 8: <u> </u><u> </u><u>8</u><u>,</u><u> </u><u>1</u><u>6</u><u>,</u><u> </u><u>2</u><u>4</u><u> </u>
multiples of 12: <u> </u><u> </u><u>1</u><u>2</u><u>,</u><u> </u><u>2</u><u>4</u><u> </u>
Step-by-step explanation:
Answer:
100.9 yards
Step-by-step explanation:
One circuit of the track is a distance of ...
C = 2πr = 2π(60 yd) = 120π yd.
At Alex's running rate, the distance covered in 20 minutes is ...
(4 yd/s)(20 min)(60 s/min) = 4800 yd
The number of circuits will be ...
(4800 yd)/(120π yd/circuit) = 40/π circuits ≈ 12.7324 circuits
The last of Alex's laps is more than half-completed, so the shortest distance to his starting point is 13 -12.7324 = 0.2676 circuits,
That distance is (0.2676 circuits)×(120π yd/circuit) ≈ 100.88 yd
The shortest distance along the track to Alex's starting point is about 100.9 yards.
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<em>Additional comment</em>
The exact distance is 120(13π-40) yards. The distance will vary according to your approximation for pi. If you use 3.14, this is about 98.4 yards.
The first thing we must know is the following definition:
d = v * t
Where,
d: distance
v: speed
t: time
Therefore, the total distance traveled in this case is:
(5.5) * (0.5) + (1.5) * p = 13.25
Rewriting:
2.75 + 1.5p = 13.25
Clearing the value of p we have:
p = (13.25-2.75) / (1.5)
p = 7
Answer:
an equation representing this situation is:
2.75 + 1.5p = 13.25
DeAngelo's rate for the last 1.5 hours of his run is 7 miles per hour
