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k0ka [10]
3 years ago
11

Will give brainliest!!!!!!

Mathematics
1 answer:
maksim [4K]3 years ago
3 0

A) P is the current value so P is $2,500.

r is the annual percentage rate which is 2.7% BUT it must be written as a decimal.

\frac{100 + 2.7}{100}  = 1.027

so r is 1.027.

n is 4 because it is compounded quarterly which is 4 times per year.

B) now substitute these values into the formula and now you know that t is 7 as it says in the question

2500 \times ({1 +  \frac{1.027}{4} }^{7 \times 4} )

when you type this into the calculator, you should round your answer to 2 decimal places as you are considering money.

therefore, the answer is $1,502,827.17

hope this helps! have a good day ~ •lipika•

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Please help me with my math problem 25 points for the step-by-step explanation.
Ghella [55]

Step-by-step explanation:

S + L = 6 => L= 6-S

8S + 10L = 56

8S + 10(6-S) = 56

8S +60 -10S = 56

-2S = 56-60

-2S = -4

S = -4/-2

S = 2

=> S = small notebook = 2

L = large notebook = 6-2 = 4

5 0
3 years ago
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Find the sum<br> 3/4 + 1/2=
Angelina_Jolie [31]

Answer: 3/4+1/2= 1¼

Step-by-step explanation:

1/2= 2/4 3/4+2/4=1¼

7 0
3 years ago
In a fraternity with 40 members , 18 take mathematics, 5 take both mathematics and physics, and 8 take neither mathematics nor p
garri49 [273]

Answer: 14 members take physics but not mathematics

Step-by-step explanation:

Please see the attached for a diagrammatic representation of this situation.

Since there are 40 members but 8 did not offer any of mathematics or physics, then:-

40 - 8 = 32

So, 32 members of the fraternity offer maths, physics or both.

5 members offer both mathematics and physics .

Since 5 members offer both mathematics and physics, the number of members that offer maths alone = 18 - 5

Let us use "P" to represent the number of members that offer physics. Therefore, the number of members that offer only physics = (P - 5)

Now, if we add up the members that offered maths only, the members that offered both mathematics and physics and the members that offered only physics, it will be equal to the 32 members that offered at least a subject.

Therefore, (18 - 5) + 5 + (P - 5) = 32

18 - 5 + 5 + P - 5 = 32

18 + P - 5 = 32

P + 13 = 32

P = 32 - 13

P = 19

19 members offered physics out of the 32 members that offered maths, physics or both.

To find out the number of people or members that offered physics only, we subtract the number of members that offered the two subjects (5) from a total of 19 members that offered Physics

19 - 5 = 14

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5 0
3 years ago
Read 2 more answers
If EF bisects CD.CG = 5x - 1, GD = 7x-13, EF = 6x - 4, and GF = 13. find EG.
Iteru [2.4K]

Answer:

EG = 19

Step-by-step explanation:

* Lets explain how to solve the problem

- If a line bisects another line that means the point of intersection

 divides the second line into two equal parts

∵ EF bisects CD at G

∴ CG = GD

∵ CG = 5x - 1

∵ GD = 7x - 13

∴ 7x - 13 = 5x - 1

* Lets solve the equation

∵ 7x - 13 = 5x - 1

- Subtract 5x from both sides and add 13 to both sides

∴ 7x - 5x = 13 - 1

∴ 2x = 12

- Divide both sides by 2

∴ x = 6

- Point G divides EF into two parts EG and GF

∴ EF = EG + GF

∵ EF = 6x - 4

- Substitute the value of x to find EF

∵ x = 6

∴ EF = 6(6) - 4 = 36 - 4 = 32

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∵ GF = 13

- Substitute the values of EF and GF in the equation of EF

∴ 32 = EG + 13

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3 0
4 years ago
Needs halp wit dis uuuuhhhhhhh question, hhhhhhhhhhh i hate math-
drek231 [11]

Given:

3x(x - 2) + 2 and 2x² + 3x -12

If x = 7 then,

= 3(7)(7 - 2) + 2

= 21(5) + 2

= 107

= 2(7)² + 3(7) -12

= 2(49) + 21 -12

= 98 + 9

= 107

<em>For x = 7, each expression has a value of 107.</em>

<em />

If x = 2 then,

= 3(2)(2 - 2) + 2

= 6(0) + 2

= 2

= 2(2)² + 3(2) -12

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<em>For x = 2, each expression has a value of 2.</em>

<em>These results suggests that the expressions are equivalent, but (I don't know the choices) the expressions are equivalent. </em>

5 0
3 years ago
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