First do 3x3, which is 6.
Then do 1/2 x 1/2. Convert the 1/2's to .50's
Do .50 x .50. Start with 5 x 5, and get 25. Then move decimal 2 places over.
Now that you have 6 and .25, add them and get 6.25.
.25 as a fraction is, of course, 1/4
Your final answer should be 6 1/4
3x^2 – 5x – 12 = (3x+4<span>)</span>(x-3)
x^2 -9 = (x-3<span>)</span>^2
<span>8x^3+ 12x^2 - 2x - 3 = (4x^2 -
1)(2x + 3)
</span>12x^2 +16x -3= (6x - 1)(2x + 3)
x^2 + 8x - 9= (x + 9<span>)</span>(x - 1) (I <span>can not</span> see
who it can all be positive<span> ;</span>_;<span> )</span>
<span>3(x + y) + a(x + y)= (3x + 3y) + (ax + ay)</span>
Answer:
B is correct
Step-by-step explanation:
The vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5
<h3>How to rewrite the
quadratic function?</h3>
The quadratic function is given as:
f(x) = x^2 - 3x
Differentiate the function
f'(x) = 2x - 3
Set the function to 0
2x - 3 = 0
Add 3 to both sides
2x = 3
Divide by 2
x = 3/2
Set x = 3/2 in f(x) = x^2 - 3x
f(x) = 3/2^2 - 3 * 3/2
Evaluate
f(x) = -9/5
So, we have:
(x, f(x)) = (3/2, -9/5)
The above represents the vertex of the quadratic function.
This is properly written as:
(h, k) = (3/2, -9/5)
The vertex form of a quadratic function is
f(x) = a(x - h)^2 + k
So, we have:
f(x) = a(x - 3/2)^2 - 9/5
In f(x) = x^2 - 3x,
a = 1
So, we have:
f(x) = (x - 3/2)^2 - 9/5
Hence, the vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5
Read more about vertex form at
brainly.com/question/24850937
#SPJ1
X + 7/6 = 2x - 7/6
x + 7/6 (-7/6) = 2x - 7/6 - (7/6)
x = 2x - 14/6
x (-2x) = 2x (-2x) - 14/6
-x = -14/6
x = 14/6 or 2.33
x = 2.33
hope this helps
