The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
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Im pretty sure it would be doubling the length of each side
5.5 + 2.1x + 3.8x - 4.1
5.5-4.1 +x(2.1+3.8)
1.4 +x(5.9)
5.9x+1.4
these are equivalent if there is a plus sign between 1.4 5.9x
