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kotegsom [21]
4 years ago
13

Describe how secondary consumer is dependent on the sun for its energy

Chemistry
1 answer:
ivann1987 [24]4 years ago
4 0
The sun feeds the secondary consumer's food. Without the sun, the secondary consumer food source would've died
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If 90.0 grams of ethane reacted with excess chlorine,how many grams of dicarbon hexachloride would form
tigry1 [53]

Answer:

709 g  

Step-by-step explanation:

a) Balanced equation

Normally, we would need a balanced chemical equation.

However, we can get by with a partial equation, as log as carbon atoms are balanced.

We know we will need an equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.  

M_r:    30.07          236.74

           C₂H₆ + … ⟶ C₂Cl₆ + …  

m/g:    90.0

(i) Calculate the moles of C₂H₆

n = 90.0 g C₂H₆  × (1 mol C₂H₆ /30.07 g C₂H₆)

  = 2.993 mol C₂H₆

(ii) Calculate the moles of C₂Cl₆

The molar ratio is (1 mol C₂Cl₆/1 mol C₂H₆)

n = 2.993 mol C₂H₆ × (1 mol C₂Cl₆/1 mol C₂H₆)

  = 2.993 mol C₂Cl₆

(iii) Calculate the mass of C₂Cl₆

m = 2.993 mol C₂Cl₆ × (236.74 g C₂Cl₆/1 mol C₂Cl₆)

m = 709 g C₂Cl₆

The reaction produces 709 g C₂Cl₆.

6 0
3 years ago
The complete combustion of 0.611 g of a snack bar in a calorimeter (Ccal = 6.15 kJ/°C) raises the temperature of the calorimeter
Bogdan [553]
Focus your attention to the units of the given data and the unit of the final measurement you're going to solve. Through dimensional analysis,you know that the working equation would be:

Food Value = CcalΔT/m
Food value = (6.15 kJ/°C)(1.29 °C)/0.611 g = 12.98 kJ/g

Convert kJ to cal (1 kJ = 239 cal)
Food value = 12.98*239 =<em> 3,103.28 cal/g</em>
4 0
3 years ago
3 CACO3+2H3PO4&gt;CA3(PO4)2+3 CO2+3 H2O
8090 [49]

Answer:

its hto-567-st-3=56+78=103

Explanation:

so103 is yo answer

8 0
3 years ago
Tcs food that stay in the tempature danger zone for 4 hours or longer
Fittoniya [83]
What are you trying to ask??????
3 0
4 years ago
Fumaric acid, which occurs in many plants, contains, by mass, 41.4% carbon, 3.47% hydrogen, and 55.1% oxygen. The molecular mass
lukranit [14]

Answer:

Explanation:

C = 41.4/12 = 3.43

H = 3.47/1 = 3.47

O = 55.1/16 =3.44

CHO is the skeletal formula (divide each by the lowest number above). The results are close enough to 1 to be 1.

(CHO)_x = 116

C + H + O = 29

(29) _ x = 116

x = 116/29

x = 4

So there area 4 carbons 4 hydrogens and 4 oxygens.

The correct formula is C4H4O4

3 0
3 years ago
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