Draw the product of the reaction between 2-pentanol and PBr3. You do not have to consider stereochemistry. You do not have to ex
plicitly draw H atoms. Do not include counter-ions, e.g., Na , I-, in your answer. If no reaction occurs, draw the organic starting material.
1 answer:
Answer:
2-bromopentane
Explanation:
In this case, we have a substitution. An Sn2 reaction. With this in mind, we have to identify the leaving group in this case "OH" from the 2-pentanol. The nucleophile is a "Br" atom provided by the PBr3. So, the "OH" would be replaced by "Br". If we have an Sn2 reaction we will have an inversion in the configuration. If we start with a wedge bond for "OH" we will have a dashed bond for "Br", if we have a dashed bond for "OH" we will have a wedge bond for "Br". In the 2-pentanol we have any special configuration because we don't have a chiral carbon, so we can have both options (wedge and dashed) for the product (See figure 1).
You might be interested in
Answer:
1) The Kelvin temperature cannot be negative
2) The Kelvin degree is written as K, not ºK
Explanation:
The temperature of an object can be written using different temperature scales.
The two most important scales are:
- Celsius scale: the Celsius degree is indicated with ºC. It is based on the freezing point of water (placed at 0ºC) and the boiling point of water (100ºC).
- Kelvin scale: the Kelvin is indicated with K. it is based on the concept of "absolute zero" temperature, which is the temperature at which matter stops moving, and it is placed at zero Kelvin (0 K), so this scale cannot have negative temperatures, since 0 K is the lowest possible temperature.
The expression to convert from Celsius degrees to Kelvin is:
Therefore in this problem, since the student reported a temperature of -3.5 ºK, the errors done are:
1) The Kelvin temperature cannot be negative
2) The Kelvin degree is written as K, not ºK