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Jobisdone [24]
3 years ago
8

The actual volume of the object was 34.1 mL. What is the percent error of his average result?

Chemistry
1 answer:
zysi [14]3 years ago
8 0
It’s .03 % error marist bro
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Which one of Newton's Laws fits this statement: More mass means more force needed to accelerate?
ivolga24 [154]

Answer:

Newton's Second Law

Explanation:

Newton's second law basically states that the acceleration of a body which is produced by a net force is directly proportional to the magnitude of net force applied in the same direction.

This tells us that

     F   is directly proportional to a

⇒ F= ma

So we can also state from the above equation, that when we have more mass, we need more net force to accelerate it. Here, we are keeping the acceleration constant so we can surely say that force and mass varies directly.

Therefore, we have made good use of Newton's Second Law of motion to arrive at this conclusion.

4 0
3 years ago
The strength of an atom's attraction for the electrons in a chemical bond is the atom's?
Mazyrski [523]

<span><span>Yes. An element that is highly electronegative pulls more on the electrons in a bond, such as oxygen in H20. This creates a polar bond, where there is a small negative charge on the oxygen, and a small positive charge in between the hydrogens.

</span>Credit goes to "Erin M" answered on yahoo answers a decade ago.
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3 0
3 years ago
Which choice describes a population? A. all the gray squirrels that live in a forest B. a nonliving factor in an organism's envi
goldenfox [79]
I believe D. because all the organisms that live in a lake can be a bunch of living things that would be considered a population and not a species. I canceled out B. from the get go because, I don’t believe non living organisms can be in a population ?

Please get back to me if I’m right or wrong :)
5 0
3 years ago
For the reaction of hydrogen with iodine
fenix001 [56]

Answer:

r_{H_2} = \frac{-1}{2} r_{HI}

Explanation:

Hello!

In this case, considering the given chemical reaction:

H_2(g) + I_2(g) \rightarrow 2HI(g)

Thus, by applying the law of rate proportions, we can write:

\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

r_{H_2} = \frac{-1}{2} r_{HI}

Best regards!

8 0
2 years ago
Help me ASAP PLEASEEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!
lesya692 [45]

Answer:

Cells

Explanation:

5 0
2 years ago
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