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Jobisdone [24]
3 years ago
8

The actual volume of the object was 34.1 mL. What is the percent error of his average result?

Chemistry
1 answer:
zysi [14]3 years ago
8 0
It’s .03 % error marist bro
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4 years ago
Calculate the number of pounds of CO2 released into the atmosphere when a 17.0-gallon tank of gasoline is burned in an automobil
rosijanka [135]
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8 0
3 years ago
The solubility of two slightly soluble salts of M^2+ , MA and MZ_2, are the same, 4 x 10^â4 mol/L.
LekaFEV [45]

Answer:

a) MZ₂

b) They have the same concentration

c) 4x10⁻⁴ mol/L

Explanation:

a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.

The salts solubilization reactions and their Kps values are:

MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²

MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³

Thus, the Kps of MZ₂ has a larger value.

b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.

c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:

8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.

7 0
3 years ago
What is the total number of electrons in a S2– ion?<br> (1) 10 (3) 16<br> (2) 14 (4) 18
jeka57 [31]
Sulfur normally has 16 electrons (see the periodic table), but the 2- indicates that the atom is gaining 2 electrons. because of that, the answer would be 18.
hope this helped!
4 0
4 years ago
Read 2 more answers
the specific heat of iron is 0.4494 j/g°C. how much heat energy (kj) is transferred when a 24.7 kg iron ingot is cooled from 880
guapka [62]
Answer is: 9623.85 kJ of heat is <span>transferred from iron ingot.
</span>m(Fe) = 24.7 kg · 1000 g/kg = 24700 g; mass of iron ingot.
C = 0.4494 J/g°C; t<span>he specific heat of iron
</span>ΔT = 880°C - 13°C; temperature <span>difference.</span>
ΔT = 867°C.
Q = m·C·ΔT.
Q = 24700 g · 0.4494 J/g°C ·867°C.
Q = 9623856.06 J ÷ 1000J/kJ.
Q = 9623.85 kJ.
8 0
4 years ago
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