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Fofino [41]
3 years ago
7

0.75 = 0.750 are they equal

Mathematics
2 answers:
Sliva [168]3 years ago
5 0
Yes they are the same. The number on the right just has an extra zero. You can add an infinite amount of zeros to the end of a number without changing it's value.
skad [1K]3 years ago
4 0
Yes, 0.75 and 0.750 are equal. Just because there is a zero folowing the numer doesnt mean that they arent equal the number could be 0.750000 and it would still be equal.
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27 millimeters multiplied by 1 cm/10 mm
Basile [38]
27 millimeters multiplied by 1 cm/10 mm= 2.7 centimeters

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3 years ago
Is (x − 2) a factor of f(x) = x3 − 2x2 + 2x + 3? Explain your reasoning.
Drupady [299]

Answer:

❌

Step-by-step explanation:

If (x-a) is a factor of a polynomial then the polynomial must equal zero .

Here's what I mean :

x - 2 = 0  

x = 2

(2)³-2(2)²+2(2) + 3 = 0 ❌

8 - 8 +4 +3 = 0 ❌

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Hope this helped and have a good day

6 0
2 years ago
Simplify ( Write without the absolute value sign) |x-(-12)|, if x> -120
elixir [45]

Answer:

24 ;] ;] ;]

Step-by-step explanation:

5 0
3 years ago
A performer expects to sell 5000 tickets for an upcoming concert. They plan to make a total of 311,000 in sales from these ticke
dybincka [34]

Answer:

62.2x=y

Step-by-step explanation:

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7 0
3 years ago
Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu
olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is   P(A' n B' ) = 0.8855

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A  is  P(A' n B) =0.0403

Step-by-step explanation:

From the question we are told that

   The sample size is n_s =  10000

    The number of outcome for inspector A is  n__{A}} = 742

    The number of outcome for inspector B is  n__{B}} = 745

     The number of joints judged defective by both inspector is n(A u B) =  1145

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

      P(A' n B' ) =  1 - P(A u B)

Now

       P(A\ u \ B) = \frac{n(Au B)}{n_s }

substituting values

        P(A\ u \ B) = \frac{1145}{ 10 000 }

So  

      P(A' n B' ) =  1 - \frac{1145}{10 000}

     P(A' n B' ) = 0.8855

the probability that the selected joint was judged to be defective by inspector B but not by inspector A  is mathematically represented as

     P(A' n B) =  P(A \ u \ B) -P(A)

Now

        P(A) =  \frac{n__{A}}{n_s}

substituting values

       P(A) =  \frac{742}{10 000}

So

     P(A' n B) =   \frac{1145}{10 000}  - \frac{742}{10 000}

    P(A' n B) =0.0403

7 0
4 years ago
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