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4 years ago

A) find a cartesian equation for the curve described by the given polar equation. r =3 sin g

1 answer:

6 0

Recall that r^2 = x^2 + y^2, so that r = sqrt(x^2+y^2).

y
r = 3 sin g becomes sqrt(x^2+y^2) = 3*-----------------------
sqrt(x^2+y^2)

Squaring both sides,

9y^2
x^2+y^2 = -----------------
x^2 + y^2

If this is correct (and I'm not convinced that it is), then (x^2+y^2)^2 = 9y^2
shows the relationship between x and y. Can anyone improve on this result?

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What is the simplified answer and how to find it

stiv31 [10]

There you go:), hope was helpful

7 0

4 years ago

The cheerleaders are selling tickets to a pasta dinner to raise money for new competition outfits. They plan to charge $6 per pe

kow [346]

Answer:

22 and a half ticket sold here will result in no profit situation for cheerleaders.

Step-by-step explanation:

The charge per person = $6

The total cost for dinner = $135

If cheerleaders do not make any profit , then

{ If the money earned from tickets = The money Spent} ⇒ NO PROFIT

Now, charge per person = $6

So, number of person needed to earn a total of $135

n = $\frac{\textrm{The total money needed}}{\textrm{Charge per person}}$

n = $\frac{135}{6}$ = 22.5

So, 22 and a half ticket sold here will result in no profit situation for cheerleaders.

If they sell 23 tickets, they will have a profit of $3

And if they sell 22 tickets, they will be short by $3.

5 0

3 years ago

Write a function rule to represent the sequence.

nikklg [1K]

A(n)=47+(<span>n - 1)(-15) </span>

3 0

3 years ago

PLEASE HELP WITH THIS QUESTION, ILL MARK BRAINLIEST

Travka [436]

Answer:

Step-by-step explanation:

35-original drill set price

25% or .25-the additional price

markup in decimal form- 0.25

markup in percent form- 25%

Equation-35 + 25% or 0.25

35 + 25% = 43.75

4 0

3 years ago

If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,

S_A_V [24]

Taking $y=y(x)$ and differentiating both sides with respect to $x$ yields

$\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0$

Solving for the first derivative, we have

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y$

Differentiating again gives

$\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0$

Solving for the second derivative, we have

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}$

Now, when $x=1$ and $y=2$ , we have

$\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63$

3 0

3 years ago