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Alika [10]
3 years ago
5

Evaluate the expression, using the given value of the variable. z ÷ 3 – 5z + 4(z – 2) when z = 12 A. –16 B. –96 C. –14 D. –98

Mathematics
2 answers:
Tanzania [10]3 years ago
6 0
12 ÷ 3 - 5(12) + 4(12 - 2)
= 4 - 60 + 4(10)
= -56 +40
= -16
Alexus [3.1K]3 years ago
5 0
First, you would substitute z with 12 since z = 12.
12 ÷ 3 - 5 (12) + 4 (12 - 2).
Then, you would follow the order of operations.
12 ÷ 3 - 60 + 40
4 - 60 + 40
-56 + 40
-16
So your answer is -16.

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Adams, Greensburg, Middletown, and Waldron are four towns in Indiana on a nearly straight highway. If the highway is represented
andrey2020 [161]

Answer:

W, M, A and G

Step-by-step explanation:

The question is not correct, the correct question is Adams, Greensburg, Middletown, and Waldron are four towns in Indiana on a nearly straight highway. If the highway is represented by a line, the  towns can be represented by four points: A, G, M, and W. Given that MG + WM = WG and MA = MG - AG determine the  proper order of the four towns.

Answer: The line segment addition postulate states that for a line segment AC with point B which lines on AC, then this equation holds:

AB + BC = BC

Given that MG + WM = WG, this means that point M lies between the segment WG.

Also, MA = MG - AG

MA + AG = MG, hence point A lies between segment MG

Therefore the order of the points is W, M, A and G

8 0
3 years ago
Find the volume of the rectangular prism.<br> The volume is cm?<br><br> 8 cm<br> 5 cm<br> 9 cm
dedylja [7]

Answer:

360 cm

Step-by-step explanation:

volume= length x width x height

8*5*9=360 cm

6 0
3 years ago
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Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.
My name is Ann [436]

Answer:

Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.

it is given by:  a_n = a+(n-1)d where a is the first term , n is the number of term and d is the common difference.

Given the series: 49 + 54 + 59+ ......

here, Common difference(d) = 5

First term(a) = 49

by definition we have;

For nth term

a_n = a+(n-1)d

a_n = 49+(n-1)5

a_n =49+5n -5 = 5n + 44

To write the series using summation notation for 14 terms

Summation symbol '\sum'

The series for 14th terms is given by;

\sum_{n=1}^{14}(5n +44)


5 0
3 years ago
Read 2 more answers
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