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valkas [14]
3 years ago
11

3. Simplify. * 5m3 + 2m– 7m3 – 8m

Mathematics
1 answer:
Oksanka [162]3 years ago
4 0

Step-by-step explanation:

5m³ + 2m - 7m³ - 8m

= -2m³ -6m

= -2m(m² + 3)

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Which lists all the lines that are parallel to line s?
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Is there a picture? You just threw it all in a sentence. It works better with a pic
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(-1,7);, (8,-2) write an equation of the line that passes
ruslelena [56]
The formula to find the slope of a line is m = \frac{y_2 - y_1}{x_2 - x_1} where the x's and y's are your given coordinates and m is your slope. So, plug in your coordinates and solve.

m = <span>\frac{y_2 - y_1}{x_2 - x_1}   Plug in your coordinates m = [tex] \frac{-2 - 7}{8 - -1}   Cancel out the double negative m = [tex] \frac{-2 - 7}{8 + 1}   Simplify m = [tex] \frac{-9}{9}   Divide m = -1   Now, plug that slope and one set of your given coordinates into point-slope form, [tex]y - y_1 = m(x - x_1). I'll use (-1, 7).

<span>y - y_1 = m(x - x_1)   Plug in your points and slope
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7 0
3 years ago
Need a quick answer please
Zanzabum

Answer:

8 fits the equation

Step-by-step explanation:

hope this helps

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musickatia [10]

Answer:

9,0

Why?

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

6 0
3 years ago
A cone and a cylinder have equal radius, r, and equal altitudes, h. If the slant height of the cone is l, then the ratio of the
77julia77 [94]

Given:

radius of cone = r

height of cone = h

radius of cylinder = r

height of cylinder = h

slant height of cone = l

Solution

The lateral area (A) of a cone can be found using the formula:

A\text{ = }\pi rl

where r is the radius and l is the slant height

The lateral area (A) of a cylinder can be found using the formula:

A\text{ = 2}\pi rh

The ratio of the lateral area of the cone to the lateral area of the cylinder is:

\pi rl\text{ : 2}\pi rh

Canceling out, we have:

\begin{gathered} =\frac{\pi rl}{2\pi rh} \\ =\text{ }\frac{l}{2h}\text{  or l:2h} \end{gathered}

Hence the Answer is option B

3 0
1 year ago
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