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gizmo_the_mogwai [7]
3 years ago
9

Find the value of sin 50°. Round to the nearest ten-thousandth.

Mathematics
2 answers:
Brums [2.3K]3 years ago
8 0
The answer is 0.7660
Gekata [30.6K]3 years ago
3 0

Answer:

\text{sin}(50^{\circ})\approx 0.7660

Step-by-step explanation:

We are asked to find the value of \text{sin}(50^{\circ}) and round our answer to the nearest ten-thousandth.

Using the calculator we get the value of \text{sin}(50^{\circ})=0.766044443119.

To round our answer to the nearest ten-thousandth means, we need to round our answer to 4 places after decimal.

We can see that the ten-thousandth value is 0 and its next digit is 4. Since the first digit dropped is less than 5, therefore, our last digit kept will remain unchanged that is 0.

Upon rounding our answer to the nearest ten-thousandth we will get,

\text{sin}(50^{\circ})\approx 0.7660

Therefore, the value of \text{sin}(50^{\circ}) is approximately 0.7660.

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Answer:

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Step-by-step explanation:

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3 years ago
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Determine the equation of the line with slope 3 that passes through the point M(1, 2).
Mandarinka [93]

Answer:

Step-by-step explanation:

We are given the slope along with an (x, y) coordinate with which to write the equation.  You could use this info in the slope-intercept form and solve for b, or you could use this info in the point-slope form and solve it for y.  Trust me when I tell you that either one will get you the correct equation.  Promise!  I used the point-slope form, just because.  ; )

y - 2 = 3(x - 1) and

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4 0
2 years ago
Please answer my question below<br> Will give you a brainliest?
VARVARA [1.3K]

Answer:

1: 3\sqrt2 - \sqrt14

2: \sqrt21 - 2\sqrt(7)

3: 4\sqrt3 - \sqrt15

4: 2\sqrt5 - \sqrt10

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I already gave you these answers man

Step-by-step explanation:

7 0
3 years ago
A blue jay lives in a nest that is 12 meters high in a tree the blue jay flies 15 meters to get from its nest to a flower on the
Ivan

Answer:

The distance between the base of the tree and the flower is 9m

Step-by-step explanation:

Here, we have to paint a picture.

The flower is on the ground, the height of the tree is 12m.

The distance from the nest to the flower on the floor is 15m

Indisputably, what we have is a right angled triangle, with the height being 12m, the length of the hypotenuse being 15 and we are asked to calculate the adjacent which represents the distance from the base of the tree to the flower

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Please check attachment for a diagrammatic picture of the triangle

8 0
3 years ago
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3 0
3 years ago
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