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4 years ago

If y= 2x + 7 were changed to y = 5x+7, how would the graph of the new

Mathematics

1 answer:

Amanda [17]4 years ago

4 0

Answer:

C is correct

Step-by-step explanation:

Comparing the to equation with slope intercept form: $y=mx+c$

The second equation has the greatest slope, which is indicating that the line is steeper.

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One solution 19x+18=-19x+18

masya89 [10]

19x + 18 = -19x + 18

19x + 19x = 18 - 18

38x = 0

x = 0

3 0

3 years ago

Help Help!!!!!!!!!!!!!!!

BabaBlast [244]

Answer:

$\frac{7}{10} y$

Step-by-step explanation:

To add fractions <em>with the same denominator</em>, simply add the numerators:

$\frac{a}{b} + \frac{c}{b} = \frac{a+c}{b}$

So:

$\frac{3}{10} y+\frac{4}{10} y=\frac{7}{10} y$

6 0

3 years ago

Please help I will mark brainlest

spin [16.1K]

Hope this helps, pls mark me brainliest

4 0

3 years ago

The number of hours required to do a job varies inversely as the number of people working. It takes 8 hours for 4 people to pain

dezoksy [38]

Answer: it will take 5 people 6.4 hours to do the work.

Step-by-step explanation:

The number of hours required to do a job varies inversely as the number of people working. Let h represent the number of hours required to do the job. Let p represent the number of people working. Therefore,

h is inversely proportional to p

Introducing a constant of variation, k, it means that

h = k/p

It takes 8 hours for 4 people to paint the inside of a house. Therefore

8 = k/4

k = 8×4 = 32

The formula becomes

h = 32/p

To determine how many hours it will take 5 people to do the work, we will substitute p = 5 into the formula. It becomes

h = 32/5 = 6.4 hours

7 0

3 years ago

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min. If one such class is r

svp [43]

Answer:

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.

This means that $a = 50, b = 52$

If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.

$P(51.5 \leq X \leq 51.7) = \frac{51.7 - 51.5}{52 - 50} = \frac{0.2}{2} = 0.1$

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.

3 0

3 years ago