Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Answer:
159
Step-by-step explanation:
k (9) = (2 * 
) - 3
= (2 * 81) - 3
= 162 - 3
= 159
Answer:Answer:
Option (c) is correct.
function representing the increase of bacteria every hour x,
Step-by-step explanation:
Given : A colony contains 1500 bacteria. The population increases at a rate of 115% each hour.
we have to find the function that represents the given scenario.
Let x represents the number of hours elapsed.
Given A colony contains 1500 bacteria
and number of bacteria is increasing at a rate of 115% each hour.
Using formula for Compound interest , we have,
Where A is amount
T is time period
R is rate of interest
Here, P = 1500
T = x hours
R = 115%
Let f(x) be the function representing the increase of bacteria every hour.
Substitute, we have,
Simplify, we get,
Thus, function representing the increase of bacteria every hour x,
Answer:
11.06 meters
Step-by-step explanation:
Given that
The height of a regulation soccer goal is 2.4 meters
And, the distance is 10.8 meters
We need to find out the hypothesis
Here we applied the pythagoreans theorem
So,
= √ (2.4m) ^2 + (10.8 m) ^2
= √5.76 m^2 + 116.64m^2
h = 11.06 m
Hence, the hypothesis is 11.05 meters
