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IrinaVladis [17]
3 years ago
10

Whats 2/3 times negative 6/10

Mathematics
1 answer:
Fed [463]3 years ago
5 0
The answer is
-  \frac{2}{5}
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Broderick deposits $6,000 in an account that earns 5.5% simple interest paid annually. How long will it be before the total amou
emmainna [20.7K]
<span>i=prt 
where i is interest (9000-6000 = $3000 interest) 
p is principle ($6000) 
r is rate (5.5%) [taking that its 5.5%pa] 
t is time 

substitute these into the equation 
3000 = $6000 x 5.5% x t 
t = 3000 divided by (6000x5.5%) 
= 3000 divided by 330 
t=100/11 years 
 it would take 100/11 years which is approx 9.1 years</span>
6 0
3 years ago
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Write an equation in slope-intercept form with a
lora16 [44]
Your equation would be:
D. y = 10x + 6
5 0
3 years ago
Flying against the wind, a jet travels 2190 miles in 3 hours. Flying with the wind, the same jet travels 9520 miles in 8 hours.
dezoksy [38]

Answer:

Velocity of jet in still air is 970 miles per hour and velocity of wind is 210 miles per hour.

Step-by-step explanation:

Jet's velocity against wind is

3040/4 = 760 miles per hour and flying with wind it is

8260/7 = 1180 miles per hour.

Let the velocity of jet in still air be x miles per hour and velocity of wind be y miles per hour.

As such its velocity against wind is x − y and with wind is x + y and therefore

x − y = 760 and x + y = 1180

Adding the two 2 x = 1940 and x = 970 and y = 1180 − 970 = 210

Hence velocity of jet in still air is 970 miles per hour and velocity of wind is

210 miles per hour.

Actual Answer:

https://socratic.org/questions/flying-against-the-wind-a-jet-travels-3040-miles-in-4-hours-flying-with-the-wind

7 0
3 years ago
Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel
Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (x_o, y_o, z_o) and are parallel to \dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct

x = 4 + t

y = -5 + 2t

z = 2 + t

Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

\begin  {vmatrix} x = 4+ t   \\ \\  \dfrac{x-4}{1} = t  \begin {vmatirx} \end {vmatrix}\begin {vmatrix} y = - 5+2t  \\ \\ \dfrac{y+5}{2}  =t      \end {vmatrix}\begin {vmatrix} z =2+t  \\ \\ \dfrac{z-2}{1}  =t      \end {vmatrix}

∴

\dfrac{x-4}{1}= \dfrac{y+5}{2}=\dfrac{z-2}{1}

8 0
3 years ago
ASAP GUYS PLEASE I NEED UR HELP THIS IS SO HARD<br> Solve: 5 − 7 ( z + 1 ) = 7 ( − 9 − 3 z )
pantera1 [17]

Answer:

-\frac{61}{14}

Step-by-step explanation:

Question: 5 - 7(z+1) = 7(-9-3z)

We multiply the number in front of the bracket first, since that is multiplication.

--> 5 -7z -7 = -63 - 21z

--> -7z -2 = -63 - 21z

Now, we move all the z and all the numbers to each side.

--> -7z +21z = -63 +2

--> 14z = -61

--> z = -61/14

This cannot be simplified further, so z is -61/14.

6 0
1 year ago
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