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damaskus [11]
3 years ago
10

ANSWER QUICK PLEASE If f(x) = |x – 5| + 3, find f(2).

Mathematics
1 answer:
Ivanshal [37]3 years ago
6 0

Answer:

SO if f(x)= |x-5|+3 then F(2)= 6

Step-by-step explanation:

These signs |  | mean that it is an absolute value equation. SO that means any negative will automatically change to positive values and positive values will stay at positive values. You are supposed to substitute 2 in for x and if you do 2-5 then that is negative 3 but it changes to positive 3 and add three and then f(2)= 6


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Me.Durham is contemplating which chauffeured car service to the airport. The first costs $30 up front and $3 per kilometer. The
Semmy [17]

Answer: 45 dollars and it was a distance of 5 kilometers

Step-by-step explanation: What i did was start with 30, then keep adding 3 till i got the a multiple of 5.

30 + 3 = 33

33 + 3 = 36

36 + 3 = 39

39 + 3 = 42

42 + 3 = 45

So already i know that it is 5 kilometers, because i added 3 to 30 five times.

No i will do that with the second company

20 + 5 = 25

25 + 5 = 30

30 + 5 = 35

35 + 5 =  40

40 + 5 = 45

That is also 5 kilometers, because i added 5 to 20 five times. I also know they are the same price, because they both added to 45 dollars.

Thats how i solved it.

I really hope that helps!

8 0
2 years ago
I don't know how to do this please help
AveGali [126]
5z>15-----subtract 2 on both sides
z>3----divide by 5
therefore, z must equal -10, or -4
8 0
3 years ago
The population of Algebraville is 500,000 and growing at 6.25%. How many people will live in Algebraville in 10 years? 20?
otez555 [7]
This would be exponential growth
A= 500,000(1+.0625)^10
=500,000(1.0625)^10
=500,000* <span>1.83353577126
the population after 10 years= </span><span>916,767
A=500,000(1+.0625)^20
=500,000(1.0625)^20
=500,000* 3.36185342451
the population after 20 years would be= </span><span>1,680,926</span>
8 0
3 years ago
Determine the volume of the figure. Use 3.14 for π. Round your answer to the nearest tenth. Show all of your work.
Ostrovityanka [42]

Answer:

1985 cubic units (written as un. with the cubed exponent)

Step-by-step explanation:

First, you find the volume of the cylinder

Here's the formula:

V=\pi r^{2}h\\V=volume\\r=radius\\h=height

Now, you plug in and solve.

V=(3.14)(7.2^{2})(7.4)\\V=(3.14)(51.84)(7.4)\\V=(162.7776)(7.4)\\V=1204.55424\\rounded:\\V=1204.6

Then, you find the volume of the dome.

Here's the formula:

volume/of/a/sphere=\frac{4}{3}\pi r^{3}\\volume/of/a/dome:\\V=\frac{2}{3}\pi r^{3} \\V=volume\\r=radius

Now, you just plug in and solve.

V=(\frac{2}{3})(\pi)(r^{3})\\V=(\frac{2}{3})(3.14)(7.2^{3})\\V=(\frac{2}{3})(3.14)(373.248)\\V=(2.093)(373.248)\\V=781.208064\\rounded:\\V=781.2

Finally, you add them together, and there's your answer!

1204.6+781.2=1985.8

Hope this helped!

<em>brainliest?</em>

8 0
2 years ago
Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are inches long, inches wide, and 8 inche
allochka39001 [22]

Answer:

- The number of small boxes that will fill the large box 1 = 64

- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

For large box 1,

Length = L = 24.25 inches

Width = W = 18 inches

Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

Length = L = 20.5 inches

Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

7 0
2 years ago
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