Answer:
05949494
Step-by-step explanation:
;_;_;_(*(*!$+$+$8 djdjskosjdhdhdjdhdjsisudjjddhjdhdhhdhdhjhs the way to sk it or to did I rnd

the domain:

the equation:

4 is in the domain
-2 is not in the domain
The answer:

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:

It's not true so -3 isn't a solution to this equation.
Answer:
Step-by-step explanation:
(x+5)^2