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nexus9112 [7]
3 years ago
8

calculate the acceleration due to gravity on the Moon. The Moon's radius is 1.74×106m1.74×106m and its mass is 7.35×1022kg7.35×1

022kg. gMoongMoon = nothing m/s 2 m/s2
Physics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

Acceleration due to gravity on the surface of moon is given as

g = 1.62 m/s^2

Explanation:

As we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

now we have

M = 7.35 \times 10^{22} kg

R = 1.74 \times 10^6 m

now we have

g = \frac{(6.67 \times 10^{-11})(7.35 \times 10^{22}}{(1.74 \times 10^6)^2}

g = 1.62 m/s^2

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15) What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of .35 m?
____ [38]

A pendulum is not a wave.

-- A pendulum doesn't have a 'wavelength'.

-- There's no way to define how many of its "waves" pass a point
every second.

--  Whatever you say is the speed of the pendulum, that speed
can only be true at one or two points in the pendulum's swing,
and it's different everywhere else in the swing.

-- The frequency of a pendulum depends only on the length
of the string from which it hangs.


If you take the given information and try to apply wave motion to it:

             Wave speed = (wavelength) x (frequency)

             Frequency  =  (speed) / (wavelength) ,

you would end up with

             Frequency = (30 meter/sec) / (0.35 meter) = 85.7 Hz

Have you ever seen anything that could be described as
a pendulum, swinging or even wiggling back and forth
85 times every second ? ! ?     That's pretty absurd. 

This math is not applicable to the pendulum.

6 0
3 years ago
An AC voltage source has an output of ∆V = 160.0 sin(495t) Volts. Calculate the RMS voltage. Tries 0/20 What is the frequency of
kupik [55]

Answer:

RMS voltage is 113.1370 V

frequency is 780.685 Hz

voltage is −158.66942 V

maximum current is  2.9739 A

Explanation:

Given data

∆V = 160.0 sin(495t) Volts

so Vmax = 160

and angular frequency = 495

time t = 1/106 s

resistor R = 53.8 Ω

to find out

RMS voltage and frequency of the source and  voltage  and maximum current

solution

we know voltage equation = Vmax sin ωt

here Vmax is 160 as given equation in question

so RMS will be Vmax / √2

RMS voltage = 160/ √2

RMS voltage is 113.1370 V

and frequency = angular frequency / 2π

so frequency = 497 / 2π

frequency is 780.685 Hz

voltage at time (1/106) s

V(t) = 160.0 sin(495/ 108)

voltage = −158.66942 V

so current from ohm law at resistor R 53.8 Ω

maximum current = voltage max / resistor

maximum current =  160 / 53.8

maximum current =  2.9739 A

8 0
3 years ago
Would you classify petroleum as a renewable or nonrenewable resource? Justify your answer in two or more complete sentences.
olchik [2.2K]

Answer:

Petroleum is a nonrenewable resource. This being because it is a natural gas that take millions of years for it to reform which means each part of it is a once in a lifetime use.

3 0
3 years ago
4.) mi/hr/s and m/s/s are units for
egoroff_w [7]

Answer:

Acceleration

Explanation:

Acceleration has units of length per time squared.

6 0
3 years ago
The nucleus of an atom can be modeled as several protons and neutrons closely packed together. Each particle has a mass of 1.67
Lady bird [3.3K]

Explanation:

The nucleus of an atom can be modeled as several protons and neutrons closely packed together.

Mass of the particle, m=1.67\times 10^{-27}\ kg

Radius of the particle, R=10^{-15}\ m

(a) The density of the nucleus of an atom is given by mass per unit area of the particle. Mathematically, it is given by :

d=\dfrac{m}{V}, V is the volume of the particle

d=\dfrac{m}{(4/3)\pi r^3}

d=\dfrac{1.67\times 10^{-27}}{(4/3)\pi (10^{-15})^3}

d=3.98\times 10^{17}\ kg/m^3

So, the density of the nucleus of an atom is 3.98\times 10^{17}\ kg/m^3.

(b) Density of iron, d'=7874\ kg/m^3

Taking ratio of the density of nucleus of an atom and the density of iron as :

\dfrac{d}{d'}=\dfrac{3.98\times 10^{17}}{7874}

\dfrac{d}{d'}=5.05\times 10^{13}

d=5.05\times 10^{13}\ d'

So, the density of the nucleus of an atom is 5.05\times 10^{13} times greater than the density of iron. Hence, this is the required solution.

7 0
4 years ago
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