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nexus9112 [7]
3 years ago
8

calculate the acceleration due to gravity on the Moon. The Moon's radius is 1.74×106m1.74×106m and its mass is 7.35×1022kg7.35×1

022kg. gMoongMoon = nothing m/s 2 m/s2
Physics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

Acceleration due to gravity on the surface of moon is given as

g = 1.62 m/s^2

Explanation:

As we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

now we have

M = 7.35 \times 10^{22} kg

R = 1.74 \times 10^6 m

now we have

g = \frac{(6.67 \times 10^{-11})(7.35 \times 10^{22}}{(1.74 \times 10^6)^2}

g = 1.62 m/s^2

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\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

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A window has a glass surface of 2907 cm2 and a thickness of 5.6 mm. Find the rate of energy transfer by conduction through this
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Answer:

2.30714 W

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Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (81-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=2.30714\ W

The rate of energy transfer is 2.30714 W

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What is needed to give a larger boulder a large acceleration?
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3 years ago
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Answer:

<em>0.25</em>

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<em></em>

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