<u>Answer:</u> The Young's modulus for the wire is 
<u>Explanation:</u>
Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.
The equation representing Young's Modulus is:
where,
Y = Young's Modulus
F = force exerted by the weight = 
m = mass of the ball = 10 kg
g = acceleration due to gravity = 
l = length of wire = 2.6 m
A = area of cross section = 
r = radius of the wire = 
(Conversion factor: 1 m = 1000 mm)
= change in length = 1.99 mm = 
Putting values in above equation, we get:
Hence, the Young's modulus for the wire is
The answer is Rh = 135 cm^3 and B = 0.05185 wh/m^2
Explanation:
Resitivity of silicon = 0.1
thickness = 100um
so, I = ma
Required to find out concentration of electron , we know that
Rh = up
By putting in the values,
Rh = 1350 x 0.1
Rh = 135 cm^3
Now consider,
Rh = 1 / Rh.q
= 1 / Rh . q
= 1 / 135 x1.609 x10^-19
= 4.6037 x 10^16 / cm^3
Vh = BIRh / w
B = Vh w/ IRh
B = -70 x10^-6 x 100 x10^-6 / 1x 10^-3 x 135 x 10^-6
B = 0.05185 wh / m^2
what are the answer choices?
Current in the wire = 2 A
Explanation:
the magnetic field is given by
B= \frac{\mu i}{2\pi r}
μo= 4π x 10⁻⁷ Tm/A
i= current
r=0.02 m
B = magnetic field= 2 x 10⁻⁵ T
2 x 10⁻⁵= (4π x 10⁻⁷)(i) / (2π*0.02)
i=2 A
