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taurus [48]
3 years ago
6

Two aluminum soda cans are charged and repel each other, hanging motionless at an angle. Which of the forces on the left can has

the greatest magnitude? T FE they are all the same impossible to tell mg Changed: Your submitted answer was incorrect. Your current answer has not been submitted.
Physics
1 answer:
swat323 years ago
7 0

Answer:

the tension is the greatest force the system

Explanation:

For this exercise we use Newton's second law, in the equilibrium condition, this means that the acceleration is zero a = 0

             

X-axis (horizontal)

           FE - Tₓ = 0

          Fe = Tₓ

Y axis (vertical)

          T_{y} - W = 0

          T_{y} = W

let's use trigonometry for the stress components

           sin θ = Tₓ / T

           Tₓ = T sin θ

           cos θ = T_{y} / T

           T_{y} = T cos θ

we substitute

           FE = T sin  θ  

           W = T cos  θ  

Since the sine and cosine function have values ​​between 0 and 1, the voltage must be greater than the electrical force and greater than the weight of the body.

Therefore the tension is the greatest force the system

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a car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 24 ft/s2. what is the dist
Maslowich

One of the key areas of science is the study of acceleration and deceleration. Any object's rate of changing velocity is referred to as its acceleration, and a negative acceleration value is referred to as deceleration.

Using beginning velocity of 50 miles per hour,

It's going to

Final speed: 73.33 ft/s, v = 0, and a2: -22 ft/s2.

Utilize the formula: v2 = v0 + 2as

n 0 = 5377.29 + (-44) s

s =5377.29/44 = 122.21 ft

v2 = u2 + 2as is the third equation of motion. We are already aware that distance is equal to average velocity times time. Either v2 = u2 + 2as or 2as = v2 - u2. The third equation of motion connects the particle's final velocity (v), initial velocity (u), constant speed (a), and displacement (S).

Speed is defined as the ratio of distance travelled to the amount of time required to cover that distance.

To know more about motion, click on the link below:

brainly.com/question/14812762

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4 0
1 year ago
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2060 × 103 seconds (about
Fittoniya [83]

Answer:

Acceleration, a=2.22\times 10^{-3}\ m/s^2

Explanation:

It is given that,

Time period of revolution of the moon, T=2060\times 10^3\ s

If the distance from the center of the moon to the surface of the planet is, h=235\times 10^6\ m

The radius of the planet, r=3.9\times 10^6\ m

Let a is the moon's radial acceleration. Mathematically, it is given by :

a=R\times \omega^2, R is the radius of orbit

Since, \omega=\dfrac{2\pi}{T}

The radius of orbit is,

R=r+h

R=3.9\times 10^6\ m+235\times 10^6\ m=238900000\ m

So, a=\dfrac{4\pi^2 R}{T^2}

a=\dfrac{4\pi^2 \times 238900000}{(2060\times 10^3)^2}

a=2.22\times 10^{-3}\ m/s^2

Hence, this is the required solution for the radial acceleration of the moon.

5 0
3 years ago
Which statement does not describe the X Games?
nikdorinn [45]

the answer Is C. ,, thank you :)

5 0
3 years ago
Does the North Pole receive more daylight hours during Winter or Summer?
MrMuchimi

Answer:

Summer begins in the Northern Hemisphere on June 20 or 21 when the North Pole is tilted a full 23.5° toward the sun. On this day, the Northern Hemisphere has the most hours of daylight, while the Southern Hemisphere has the least hours of daylight.

Explanation:

3 0
3 years ago
Read 2 more answers
Una masa de 0,5 kg está sobre una pendiente inclinada 20º sujeta mediante una cuerda paralela a la pendiente que impide que desl
jeka94

Answer:

<em>4.61 N</em>

<em></em>

Explanation:

masa = 0.5 kg

ángulo de inclinación = 20°

Peso normal de la masa = mg

donde m = masa

g = aceleración debido a la gravedad = 9.81 m/s^2

Peso normal = 0.5 x 9.81 = 4.905 N

Si la masa se mantiene en su lugar mediante una cuerda paralela al plano, y no hay fricción en la masa, entonces

La fuerza sobre la cuerda = peso normal x cos ∅

donde ∅ = 20 °

La fuerza sobre la cuerda = 4.905 x cos 20°

==><em> 4.61 N</em>

4 0
3 years ago
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