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Anton [14]
3 years ago
13

Write an equation of the line that passes through (1,2) and is parallel to the line y=−5x+4

Mathematics
2 answers:
olga_2 [115]3 years ago
5 0

Answer:

y = = -5x + 7

Step-by-step explanation:

y=−5x+4, slope = -5

Parallel lines, slopes are the same so slope of new line is also equal -5

Equation in point slope form:

y - 2 = -5(x - 1)

y - 2 = -5x + 5

y = = -5x + 7 <--------equation in slope intercept form


polet [3.4K]3 years ago
4 0

Answer:

y=-5x+7

Step-by-step explanation:

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a recently married couple are planning to have four children. They are equally likely to have a boy as well as a girl. What is t
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0.25

Step-by-step explanation:

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4 years ago
A closed box with a square base is to have a volume of 171 comma 500 cm cubed. The material for the top and bottom of the box co
Zepler [3.9K]

Answer:

C(x)=\dfrac{20x^3+1715000}{x}\\$Minimum cost, C(35)=\$29,400

The dimensions that will lead to minimum cost of the box are a base length of 35 cm and a height of 140 cm.

Step-by-step explanation:

Volume of the Square-Based box=171,500 cubic cm

Let the length of a side of the base=x cm

Volume =x^2h

x^2h=171,500\\h=\dfrac{171500}{x^2}

The material for the top and bottom of the box costs ​$10.00 per square​ centimeter.

Surface Area of the Top and Bottom =2x^2

Therefore, Cost  of the Top and Bottom =\$10X2x^2=20x^2

The material for the sides costs ​$2.50 per square centimeter.

Surface Area of the Sides=4xh

Cost of the sides=$2.50 X 4xh =10xh

\text{Substitute h}$=\dfrac{171500}{x^2} $into 10xh\\Cost of the sides=10x(\dfrac{171500}{x^2})=\dfrac{1715000}{x}

Therefore, total Cost of the box

= 20x^2+\dfrac{1715000}{x}\\C(x)=\dfrac{20x^3+1715000}{x}

To find the minimum total cost, we solve for the critical points of C(x). This is obtained by equating its derivative to zero and solving for x.

C'(x)=\dfrac{40x^3-1715000}{x^2}\\\dfrac{40x^3-1715000}{x^2}=0\\40x^3-1715000=0\\40x^3=1715000\\x^3=1715000\div 40\\x^3=42875\\x=\sqrt[3]{42875}=35

Recall that:

h=\dfrac{171500}{x^2}\\Therefore:\\h=\dfrac{171500}{35^2}=140cm

The dimensions that will lead to minimum costs are base length of 35cm and height of 140cm.

Therefore, the minimum total cost, at x=35cm

C(35)=\dfrac{20(35)^3+1715000}{35}=\$29,400

8 0
3 years ago
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