Answer:
see explanation
Step-by-step explanation:
By the rational root theorem, any rational roots of f(x) are expressible in the form
for integers p and q
with p a divisor of the constant term 6 and q a divisor of the leading coefficient 1.
The possibilities are ± 1, ± 2, ± 3, ± 6
Since the lead coefficient is 1 dividing by that number doesn't change a thing.
Thus the possible rational roots are
= - 6, - 3, - 2, -1, 1, 2, 3, 6
X=rcos(t), y=rsin(t). so y/sin(t) = r => csc(t) = r/y. so for now we have r*(r/y)=8. To solve for r, do x^2 + y^2 = r^2, so r=sqrt(x^2 + y^2). So we have sqrt(x^2 + y^2<span>)*(sqrt(x^2 + y^2<span>)/y</span>)=8, or (x^2+y^2)/y = 8, or x^2/y + y = 8.</span>
Answer:
umm im confused a bit
Step-by-step explanation: