Explain why the slope of a horizontal line is always zero

Mathematics

2 answers:

aksik [14]3 years ago

7 0

Answer:

Pretty sure its because the lines don't add up

Step-by-step explanation:

Monica [59]3 years ago

5 0

The slope of a line is always zero because the line does not move up or down on the y-axis.

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Whats the solution of x^2+4x-4=8

denpristay [2]

Answer:

x = 2, x = -6

Step-by-step explanation:

$x^2+4x-4=8$

Subtract 8 from both sides.

$x^2+4x-4-8=8-8$

Simplify.

$x^2+4x-12=0$

Solve with quadratic formula.

a = 1

b = 4

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Katen [24]

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I need help I can’t figure it out

dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$