Answer:
![s(t) = 2t^{3} - 2t^{2} + 5t - 9](https://tex.z-dn.net/?f=s%28t%29%20%3D%202t%5E%7B3%7D%20-%202t%5E%7B2%7D%20%2B%205t%20-%209)
Step-by-step explanation:
The position is the integrative of the velocity.
We have that:
![v(t) = 6t^{2} - 4t + 5](https://tex.z-dn.net/?f=v%28t%29%20%3D%206t%5E%7B2%7D%20-%204t%20%2B%205)
So
![s(t) = \int {v(t)} \, dt](https://tex.z-dn.net/?f=s%28t%29%20%3D%20%5Cint%20%7Bv%28t%29%7D%20%5C%2C%20dt)
![s(t) = \int {(6t^{2} - 4t + 5)} \, dt](https://tex.z-dn.net/?f=s%28t%29%20%3D%20%5Cint%20%7B%286t%5E%7B2%7D%20-%204t%20%2B%205%29%7D%20%5C%2C%20dt)
![s(t) = 2t^{3} - 2t^{2} + 5t + K](https://tex.z-dn.net/?f=s%28t%29%20%3D%202t%5E%7B3%7D%20-%202t%5E%7B2%7D%20%2B%205t%20%2B%20K)
In which k is the constant of integration, which we use the initial condition to find.
s(1) = -4. So
![-4 = 2*(1)^{3} - 2*(1)^{2} + 5(1) + K](https://tex.z-dn.net/?f=-4%20%3D%202%2A%281%29%5E%7B3%7D%20-%202%2A%281%29%5E%7B2%7D%20%2B%205%281%29%20%2B%20K)
![K = -9](https://tex.z-dn.net/?f=K%20%3D%20-9)
So
![s(t) = 2t^{3} - 2t^{2} + 5t - 9](https://tex.z-dn.net/?f=s%28t%29%20%3D%202t%5E%7B3%7D%20-%202t%5E%7B2%7D%20%2B%205t%20-%209)
What is the intersection of the sets A={3,4,7,9,13} and B={3,7,10,13,17}? A. null set B. {3,7,13} C. {3,4,7,9,10,17} D. {3,4,7,8
Sliva [168]
The intersection of the sets is a set with containing all the common elements. From the two sets given above, it can be seen that 3, 7, and 13 can be found from both sets. The intersection is a set with elements 3, 7, and 13. Thus, the answer to this item is letter B.
Use PEMDAS:
[(30+6) -3^2] / 9* 2
= (36 -9)/ 9* 2
= 27/9* 2
= 3*2
= 6
The final answer is 6~
Step-by-step explanation:
let the first-day ride be x
Then the second-day ride will be
=1.5
x
The third-day ride will be=1.5(1.5x)
The Fourth-day ride will be=1.5*1.5(1.5x)
hence for the four days the distance covered is
65=x+1.5x+1.5*1.5x+1.5*1.5*1.5x
65=x+1.5x+2.25x+3.375x
65=8.125x
divide both sides by 8.125 we have
x=65/8.125
x=8mile
the first-day ride be x=8miles
the second-day ride will be
=1.5
x
=1.5*8= 12miles
The third-day ride will be=1.5(1.5x) = 18miles
The Fourth-day ride will be=1.5*1.5(1.5x) = 27miles