Answer:Assuming all three, we shall find that each of the relations in 3:14 leads to a ... Then by 3:15 the relations AD//BC and AB||DE imply AD//CE, which excludes ... From 2:72, 3:11, 3:14, and 3:16 we deduce 3:19 If A, B, C are three distinct ... a point D lies between X and Y in AB/C if it belongs to XY/C, that is, if XY||CD
Step-by-step explanation:
Answer:
D. Rewrite one side (or both) using the distributive property, Yes
Step-by-step explanation:
How can we get Equation BBB from Equation AAA? Based on the previous answer, are the equations equivalent? In other words, do they have the same solution?
The formula is d=C/π.
The diameter is 2 times the radius
The formula for the circumference using the radius is 2πr.
in order to do this backwards, we would have to do 16÷2÷π, but we're not looking for the radius.
Therefore, we take out the ÷2 part, which would be 16÷π
16 is the circumference
16÷π=d
d=C÷π
Answer:
∠ 1,3,5,7 = 32°
∠2,4,6,8,= 148°
Step-by-step explanation:
From the figure attached,
AB and CD are two parallel lines and another transverse line is intersecting these line at two distinct points.
Since, m∠1 = 32°,
∠1 and ∠4 are supplementary angles [Linear pair of angles]
m∠1 + m∠4 = 180°
32° + m∠4 = 180°
m∠4 = 180° - 32°
m∠4 = 148°
therefore,
m∠1,3,5,7 = 32°
m∠2,4,6,8,= 148°
