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Mila [183]
1 year ago
11

Can someone help me? i need my math grade to go up

Mathematics
2 answers:
malfutka [58]1 year ago
8 0

Answer:

59

Step-by-step explanation:

do it piece of paper or ask someone to help you.

telo118 [61]1 year ago
8 0
The answer is 59, because 63 to the power of 3 is 21 and the other answers are decimals that are smaller
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Nathan launches a water balloon vertically from a platform on his roof. The height of the balloon (in feet) is represented by th
bulgar [2K]

Answer:

45.27feet

Step-by-step explanation:

Given the height of the balloon (in feet) represented by the equation h=−16t2+28.7t+32.4, where t is the time (in seconds)

Note that the velocity of the balloon at maximum height is zero, hence;

v = dh/dt =0

-32t+28.7 = 0

-32t = -28.7

t = 28.7/32

t = 0.897secs

Get the maximum height

Recall that h=−16t²+28.7t+32.4

h = -16(0.897)²+28.7(0.897)+32.4

h= -12.87+25.74+32.4

h = 45.27feet

Hence the maximum height reached is 45.27feet

7 0
2 years ago
I need this asap. Find the area of the following quadrilateral.
Elenna [48]

Answer:56

Step-by-step explanation:

i got it correct on my test

4 0
2 years ago
Find the quotient:<br> 8(cos275+ i sin275) / 16(cos180+ i sin180)
Art [367]

the answer is D, you divide 8 by 16 you get 2 in below the division sign, cosine 180 is -1 , sine 180 is zero so the imaginary number cancels out leaving only -1 multiplied by 2 equals -2 then cosine and sine 95 equal negative the cosine and sine of 275 you take the negative sign common factor divide it by the negative sign of 2 and you get the answer is d

5 0
3 years ago
Read 2 more answers
22. Determine the value of c so that the line
tiny-mole [99]

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints  D(c, -7) and E(5, -3).

Using slope formula: Slope=\frac{y_2-y_1}{x_2-x_1} we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}

We have:

x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \

Putting values and finding c

\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2

So, If the lines BC and DE are parallel, the value of c is c=-2

8 0
3 years ago
Can you please show the all of the steps for the problem below without derivatives?
gogolik [260]
Are you in k12 if you are i think i did it let me get it
7 0
2 years ago
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