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aniked [119]
3 years ago
12

Divide the product of 6 and 5 by the quotient of 12 and 4 please show me the expression too...

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
3 0

Step-by-step explanation:

\text{the product of 6 and 5:}\qquad6\cdot5=30\\\\\text{the quotient of 12 and 4:}\qquad12:4=3\\\\\text{Divide the product of 6 and 5 by the quotient of 12 and 4:}\\\\(6\cdot5):(12:4)=30:3=10

V125BC [204]3 years ago
3 0

Answer:

10

Step-by-step explanation:

to find the quotient of 12 and 4 u need to divide them first : (12/4)

to find to product of 6 and 5: (6*5)

since u divide the product by the quotient there is a division symbol between the two pairs of parentheses : (6*5) / (12/4)

6*5 is 30

12/4 is 3

30/3 = 10

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ella [17]

Answer:

TRUE

Step-by-step explanation:

y-4 = 2(x-1)

here, 4 is representing the y value and 1 is representing the x value.

And the slope is 2.

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2 years ago
If f(x) = -7x + 5x2 + 10, what does f(-2) equal?
aksik [14]

Answer:

f(-2) = 44

Step-by-step explanation:

Hello there! Lets get started solving this function!

For a function, whenever we see f(x) = ... , the function is simply asking the value of the equation at x! So, if replace f(x) with f(-2), we simply substitute x with -2 in the equation! Lets get started!

f(x) = -7x + 5x^{2} + 10\\f(-2) = -7(-2) + 5(-2)^{2} + 10\\f(-2) = 14 + 20 + 10\\f(-2) = 44\\

First, we can write the original function. Next, we substitute in -2 for x. Then, we find our final terms. Finally, we are given that f(-2) = 44.

Hope this helps! Remember, math is fun!

7 0
3 years ago
Solve the simultaneous equation 2p - 3q = 4, 3p + 2q = 9. <br>b. if 223= 87 find x<br>​
wolverine [178]

Answer:

Step-by-step explanation:

Given the simultaneous equation 2p - 3q = 4 and 3p + 2q = 9, to get the value of p and q we will use elimination method.

2p - 3q = 4 ...................... 1 * 3

3p + 2q = 9 ..................... 2 * 2

Multiplying equation 1 by 3 and 3 by 2:

6p - 9q = 12

6p + 4q = 18

Subtracting both equation

-9q-4q = 12-18

-13q = -6

q = -6/-13

q = 6/13

Substituting q = 6/13 into equation 2

2p - 3(6/13) = 4

2p - 18/13 = 4

2p = 4+18/13

2p = (52+18)/13

2p = 70/13

p = 70/26

p = 35/13

<em>Hence p = 35/13 and q = 6/13</em>

<em></em>

<em>b) </em>If if 223ₓ = 87 find x

Using the number base system and converting 223ₓ  to base 2 will give us;

223ₓ = 2*x² + 2*x¹ + 3*x⁰

223ₓ  = 2x²+2x+3

​

Substituting back into the equation, 2x²+2x+3 = 87

2x²+2x+3-87 = 0

2x²+2x-84 = 0

x²+x-42 = 0

On factorizing:

(x²+6x)-(7x-42) = 0

x(x+6)-7(x+6) = 0

(x+6)(x-7) = 0

x+6 = 0 and x-7 = 0

x = -6 and 7

<em>Hence the value of x is 7 (neglecting the negative value)</em>

5 0
3 years ago
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