Answer:
<em>g(x) = </em>
<em> - 3 </em>
Step-by-step explanation:
<em>g(x) = </em>
<em> - 3 </em>
Answer:
Volume of a hexagonal pyramid = 588 square meter
Step-by-step explanation:
Given:
Base area of hexagonal pyramid = 147 square meter
Height of hexagonal pyramid = 4 meter
Find:
Volume of a hexagonal pyramid
Computation:
Volume of a hexagonal pyramid = Base area of hexagonal pyramid x Height of hexagonal pyramid
Volume of a hexagonal pyramid = 147 x 4
Volume of a hexagonal pyramid = 588 square meter
1). Am I seated comfortably, with plenty of light on my paper ?
2). Is my pencil sharp ?
Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Answer:
1. True
2. False
3. False
4. True
5. False
Step-by-step explanation: