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Valentin [98]
3 years ago
12

Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator. 6.3kg : 4.5kg

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0

Answer:

63/10 : 9/2

Step-by-step explanation:

6.3 is 6 and 3/10

we can turn that into an improper fraction so its 63/10

4.5 is 4 and 1/2

we can turn this into an improper fraction with is 9/2

so now its 63/10 : 9/2 as a ratio

Hope this helps. Good luck.

kipiarov [429]3 years ago
7 0

\frac{ \frac{19}{3}kg }{ \frac{9}{2}kg }

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Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,
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Answer:

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Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

f'' = x - \frac{3}{2}

f' = \int {\left(x-\frac{3}{2}\right) } \, dx

f' = \int {x} \, dx -\frac{3}{2}\int \, dx

f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C, where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative (f'(4) = 1):

1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C

C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)

C = -1

The first derivative is y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1, and the particular solution is found by integrating one more time and using the initial condition (f(0) = 0):

y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1  \right)} \, dx

y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx

y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C

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C = 0

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

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The amount Lin's sister earns at her part-time job is proportional to the number
jarptica [38.1K]

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<u>Step-by-step explanation:</u>

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Here , Lin's sister earns $9.60 per hour . Let  x represents the hours she works and y  represents the dollars she earns . So , According to question following is the equation framed in the form of y=kx :

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Now ,  x as a function of y :

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