Question

any hour, more than 5 customers will arrive? Rot the Fidelity Credit Union, a mean of 5.8 customers arrive hourly at the drive-through window. What is the probability that, in any hour, more than 5 customers will arrive? Round your answer to four decimal places.und your answer to four decimal places.

Answer 1

Answer:

0.5217

Step-by-step explanation:

Given that:

mean $\mu$ = 5.8

Using Poisson Probability formula:

$P(X=x) = \frac{ (e^{- \mu} * {\mu^x) }}{x!}$

$P(X>5.8)=1-P(X \leq5)$

$= 1-[P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)]$

$= 1 -[\frac{(e^{-5.8}*5.8^0) }{ 0! } + \frac{(e^{-5.8}*5.8^1) }{ 1! } +\frac{(e^{-5.8}*5.8^2) }{ 2! } +\frac{(e^{-5.8}*5.8^3) }{ 3! } +\frac{(e^{-5.8}*5.8^4) }{ 4! } +\frac{(e^{-5.8}*5.8^5) }{ 5! } ]$

$=1-(0.003+0.0176+0.0509+0.0985+0.1428+0.1656)$

$=1-0.4783$

$=0.5217$

∴ the probability that, in any hour, more than 5 customers will arrive =0.5217