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Anestetic [448]
3 years ago
9

Please help I will give brainliest and 15 points

Mathematics
2 answers:
Kruka [31]3 years ago
8 0
Hi there, actually, the image that you provided us with does not have any grid or graph to mark the points on
maw [93]3 years ago
6 0

Answer:

Question

Why did you want to friend me??

Step-by-step explanation:

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Simplify: <br><br> 3c-5d+5d<br><br> Pls
Arturiano [62]

Answer:

3 c

Step-by-step explanation:

Simplify the following:

5 d - 5 d + 3 c

Hint: | Combine like terms in 5 d - 5 d + 3 c.

5 d - 5 d = 0:

Answer: 3 c

5 0
3 years ago
Read 2 more answers
What's the probability of obtaining a 3 digit number at random which is DIVISIBLE by 7 ​
pochemuha

Answer:

  32/225 ≈ 0.1422

Step-by-step explanation:

If you consider "3-digit" numbers to be between 100 and 999, inclusive, there are 128 such numbers divisible by 7. The probability of choosing one at random is ...

  128/900 = 32/225 = 0.1422...(repeating)

__

If you consider all non-negative integers less than 1000 to be "3-digit numbers," then the probability is ...

  142/1000 = 0.142 (exactly)

6 0
3 years ago
The cost for a pack of 24 pens is $4.08 . Find the unit price in dollars per pen. If necessary, round your answer to the nearest
Eduardwww [97]

Answer:

The unit price is 0.17 cents per pen.

4 0
3 years ago
The diagonals of a rhombus have lengths of 12 centimeters and 16 centimeters. what is the length of one side of the rhombus
Yuki888 [10]
<span>Diagonals of a rhombus are perpendicular and bisect each other. This means this rhombus is composed of four right triangles with legs of length 6 cm and 8 cm, with their hypotenuses forming the perimeter of the rhombus. The Pythagorean theorem a^2+ b^2 = c^2 can be used to find the length of the hypotenuse. 6^2+8^2 = 36+64 = 100. The square root of 100 is 10, so the length of a side of the rhombus is 10 cm.</span>
5 0
3 years ago
What is the arc measure of BDC in degrees?<br> (4k + 159)<br> P<br> (2k + 153)
andre [41]
<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

(4k + 159)^{\circ}

And another arc, let's call it FGH. measures:

(2k + 153)^{\circ}

If those arc are equal, then this equation is true:

(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3

Substituting k into the first equation:

\angle BDC=(4(-3)+159)^{\circ} \\ \\ \angle BDC=(-12+159)^{\circ} \\ \\ \boxed{\angle BDC=147^{\circ}}

3 0
3 years ago
Read 2 more answers
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