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3 years ago

7

Two cars head toward each other from opposite ends of a freeway 2286 miles long. If the speed of the first car is 68 miles per h

our and the speed of the second car is 59 miles per hour, how long will it take before the cars pass each other? hours

1 answer:

exis [7]3 years ago

3 0

Answer:

Step-by-step explanation:

multiply 68*59

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What is the distance between the points (14, 29) and (14, 58) in the coordinate plane?

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$Distance= \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1})^2} = \sqrt{(58-29)^{2}+(14-14)^{2}} =29

But because x_{1}=x_{2}, 

 and it is a vertical segment, 

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3. There are four teams in the raquetball league on the island of Allendine. In a season, they play each other once. Three point

andrew-mc [135]

Answer and Step-by-step explanation:

Team: Points. Results fetching points

Arcadia. 3+1. 1 win & 1 draw

Brextone. 3+1. 1 win & 1 draw

Cremore 1+1. 2 draws

Dunross. 3+3. 2 wins

a) Based on the previous data, we can conclude that the number of matches drawn was 4

b) Dunross defeated cremore since cremore did not win any league game and dunross reported no ties

c) Yes, you can get a prediction of the matches with their respective results as follows

Brextone drew with Cremore

Dunross beat Arcadia

Arcadia beat Brextone

Arcadia drew with Cremore

Dunross beat Cremore

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The base of each pyramid is an isosceles triangle. Which has the greater surface area?

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The base is the greatest surface area

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3 years ago

MATH HELP PLEASE!!! PLEASE HELP!!!

grandymaker [24]

The answer is: [C]:  " f(c) = $\frac{9}{5}$ c + 32 " .
________________________________________________________

Explanation:
________________________________________________________
Given the original function:

" c(y) = (5/9) (x <span>− 32) " ; in which "x = f" ; and "y = c(f) " ;
________________________________________________________
</span>→ <span>Write the original function as: " y = </span>(5/9) (x − 32) " ;

Now, change the "y" to an "x" ; and the "x" to a "y"; and rewrite; as follows:
________________________________________________________
x = (5/9) (y − 32) ;

Now, rewrite THIS equation; by solving for "y" ; in terms of "x" ;
_____________________________________________________
→ That is, solve this equation for "y" ; with "c" as an "isolated variable" on the
"left-hand side" of the equation:

We have:

→ x = " ( $\frac{5}{9}$ ) * (y − 32) " ;

Let us simplify the "right-hand side" of the equation:
_____________________________________________________

Note the "distributive property" of multiplication:
__________________________________________
a(b + c) = ab + ac ; <u><em>AND</em></u>:

a(b – c) = ab – ac .
__________________________________________

As such:
__________________________________________

" ( $\frac{5}{9}$ ) * (y − 32) " ;

= [ ( $\frac{5}{9}$ ) * y ]   − [ ( $\frac{5}{9}$ ) * (32) ] ;

= [ ( $\frac{5}{9}$ ) y ]  − [ ( $\frac{5}{9}$ ) * ( $\frac{32}{1})$ " ;

= [ ( $\frac{5}{9}$ ) y ]  − [ ( $\frac{(5*32)}{(9*1)}$ ] ;

= [ ( $\frac{5}{9}$ ) y ]  − [ ( $\frac{(160)}{(9)}$ ] ;

= [ ( $\frac{5y}{9}$ ) ]  − [ ( $\frac{(160)}{(9)}$ ] ;

= [ $\frac{(5y-160)}{9}$ ] ;
_______________________________________________
And rewrite as:

→ " x = $\frac{(5y-160)}{9}$ " ;

We want to rewrite this; solving for "y"; with "y" isolated as a "single variable" on the "left-hand side" of the equation ;

We have:

→ " x = $\frac{(5y-160)}{9}$ " ;

↔ " $\frac{(5y-160)}{9}$ = x ;

Multiply both sides of the equation by "9" ;

9 * $\frac{(5y-160)}{9}$ = x * 9 ;

to get:

→ 5y − 160 = 9x ;

Now, add "160" to each side of the equation; as follows:
_______________________________________________________

→ 5y − 160 + 160 = 9x + 160 ;

to get:

→ 5y = 9x + 160 ;

Now, divided Each side of the equation by "5" ;
to isolate "y" on one side of the equation; & to solve for "y" ;

→ 5y / 5 = (9y + 160) / 5 ;

to get:

→ y = (9/5)x + (160/5) ;

→ y = (9/5)x + 32 ;

→ Now, remember we had substituted: "y" for "c(f)" ;

Now that we have the "equation for the inverse" ;
→ which is: " (9/5)x + 32" ;

Remember that for the original ("non-inverse" equation); "y" was used in place of "c(f)" . We have the "inverse equation"; so we can denote this "inverse function" ; that is, the "inverse" of "c(f)" as: "f(c)" .

Note that "x = c" ;
_____________________________________________________
So, the inverse function is: " f(c) = (9/5) c + 32 " .
_____________________________________________________

The answer is: " f(c) = $\frac{9}{5}$ c + 32 " ;
_____________________________________________________
→ which is:

→ Answer choice: [C]: " f(c) = $\frac{9}{5}$ c + 32 " .
_____________________________________________________

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3 years ago

what is the sum of the first five ferms of a geometric series with a1=10 and r=1/5? express your answer as an important fraction

mote1985 [20]

The sum of any geometric sequence, (technically any finite set is a sequence, series are infinite) can be expressed as:

s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=term number

Here you are given a=10 and r=1/5 so your equation is:

s(n)=10(1-(1/5)^n)/(1-1/5) let's simplify this a bit:

s(n)=10(1-(1/5)^n)/(4/5)

s(n)=12.5(1-(1/5)^n) so the sum of the first 5 terms is:

s(5)=12.5(1-(1/5)^5)

s(5)=12.496

as an improper fraction:

(125/10)(3124/3125)

390500/31240

1775/142

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3 years ago