16.5 degrees below the starting temp, whatever that is. If its 0, then -16.5 degrees.
The first equation would be (.5)5-11=-8.5, because the metal has been cooling for 5 hours.
The device that 'aids' in the cooling would be -5-3=-8, because it is a separate variable that cools the metal, so the amount the device cools is independent of the natural cooling amount, and the equation is independent of the natural cooling equation.
You then add -8.5 and -8, because the device has lowered 8.5 degrees and 8 degrees. This equals -16.5 degrees, or a decrease of 16.5 degrees.
Wouldnt it be the out side numbers ?at both ends?
Answer:
I pretty sure the answer is Nervous
Answer:
try restarting it or re downloading
<span>△PQR is similar to △STU
</span>m∠R = m∠U = 96°
m∠Q = m∠T = 6
m∠P = 180 - ( 96 + 6)
m∠P = 180 - 102
m∠P = 78
answer
m∠P = 78
