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Mariulka [41]
3 years ago
11

The table shows the battery life of four different mobile phones:

Mathematics
1 answer:
Pie3 years ago
4 0

Answer:

A 20

Step-by-step explanation:

Given

Phone Battery Life (hours)

A 20

B 25

C 10

D 18

8.45% of the battery life of each mobile phone is used in a day by a typical user

Calculating Hours of battery life in a day for each mobile

A 20

Battery life for A = \frac{8.45}{100}\times 20 = 1.69hours

B 25

Battery life for B = \frac{8.45}{100}\times 25 = 2.11hours

C 10

Battery life for C = \frac{8.45}{100}\times 10 = 0.845hours

D 18

Battery life for D = \frac{8.45}{100}\times 18 = 1.52hours

Therefor Mobile phone A 20  uses a total of 1.69 hours of battery life in a day

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Marat540 [252]

The answer of this question is 42


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A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu
yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm,  C2 = 0.0062 m = 0.62 cm

B)  A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = \sqrt[4]{3} is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

f(t) = 10sin(t) N

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speed of mass = 4 cm/s = 0.04 m/s

initial velocity = 3 cm/s = 0.03 m/s

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y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m

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f(t) = 10sin(t/2) N

using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)

A) finding the solution of the initial value

attached below is the solution and

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C attached below

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Answer:

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Step-by-step explanation:

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